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melomori [17]
3 years ago
10

The area of a regular hexagon inscribed in a circle with radius 2 is . Round your answer to the nearest tenth.

Mathematics
1 answer:
Verdich [7]3 years ago
6 0

Answer:

10.4 to nearest tenth.

Step-by-step explanation:

If we draw lines from the centre of the circle to each vertex of the hexagon we get 6  equilateral triangles  of side length 2.

Altitude of each triangle  = sqrt(2^2 - 1^2)

= sqrt3.

So the area of 1 triangle = 1/2 * 2 * sqrt3

= sqrt3

Therefore the area of the hexagon = 6 * sqrt3

= 6sqrt3

= 10.3923

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Please help!!! It's due rn!​
nexus9112 [7]

Step-by-step explanation:

In triangles BAD and BCD ,

BD=BD (common)

angle BDA= angle BCD {90°each(given)}

AD=DC (given)

.•. traingle BAD is congruent to triangle BCD (SAS criterion)

Hence , angle A = angle C (CPCT)

8 0
2 years ago
Can someone please help?
bonufazy [111]

Answer:

Step-by-step explanation:

8b-4b+8-3=4b+5

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6 0
3 years ago
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What is (2m+7)+(4d+6)
SpyIntel [72]

Answer:

4d+2m+13

Step-by-step explanation:

5 0
3 years ago
Solve the 3x3 system shown below. Enter the values of x, y, and z.
slamgirl [31]

Answer:

x = 1

y = -1

z = 2

Step-by-step explanation:

You have the following system of equations:

x+2y-z=-3\ \ \ \ \ (1)\\\\2x-y+z=5\ \ \ \ \ \ (2)\\\\x-y+z=4\ \ \ \ \ (3)

First, you can subtract euqation (3) to equation (1):

x + 2y - z = -3

<u>-x +y  -z = - 4 </u>

0   3y  -2z = -7    (4)

Next, you can multiply equation (3) by 2 and subtract it to equation (2):

2[ x -y + z = 4]

<u> -2x +y -z = -5</u>

  0 -y + z= 3     (5)

You multiply equation (5) by 2 and sum (5) with (4):

2[ -y  + z = 3]

<u>    3y  -2z= -7</u>

  y  + 0 = -1

Then y = -1

Next, you replace y=-1 in (5) to obtain z:

-(-1) + z = 3

z = 2

Finally, you can replace z and y in the equation (3) to obtain x:

x - (-1) + (2) = 4

x = 1

7 0
3 years ago
Simplify using order of operations.Show all your work. 4^3 + (`10-8) divided by 2
Igoryamba

Answer:

<h2>65</h2>

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

------------------------------------------------------------------------

4^3+(10-8)\div2=64+2\div2=64+1=65

3 0
3 years ago
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