The width of the cooling tower at the base of the structure will be A. 36 meters.
<h3>How to calculate the width?</h3>
From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.
Therefore, the width of the cooling tower at the base of the structure will be:
= 2 × ✓324
= 2 × 18
= 36
In conclusion, the width is 36 meters.
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Answer:
n^22 (I love your profile picture by the way)
Step-by-step explanation:
All are equal except A/D = C/B
I replaced the values with numbers
a=5 b=10 c=50 d=100
10/5=100/50 so it’s not b/a = d/c
5/10=50/100 so it’s not a/b = c/d
5/50 = 10/100 so it’s not a/c = b/d
5/100 is NOT 50/10 so it’s NOT a/d = c/b