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zvonat [6]
2 years ago
5

How can you get the variable alone in the equation 25? 5 a

Mathematics
2 answers:
WARRIOR [948]2 years ago
5 0

Answer:

5

Step-by-step explanation:

5x5=25

or

5xa=25

a=5

vampirchik [111]2 years ago
5 0

Answer:

a=5

Step-by-step explanation:

The basic technique to isolate a variable is to “do something to both sides” of the equation, such as add, subtract, multiply, or divide both sides of the equation by the same number.

\frac{5a}{5} =\frac{25}{5}

a=5

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U=1-3v/vt-w make t the subject<br> Answer for it
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Answer:

t= -\frac{u}{3}+\frac{1}{3}-\frac{w}{3}

Step-by-step explanation:

Divide each side with variables by the one without them.

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2 years ago
Harry collects data from a random sample of seventh-graders. Out of 25 respondents, 10 ride the bus home. Of the 150 seventh-gra
alekssr [168]

10/25=x/150

x=60

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answer simple

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2 years ago
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The function y = f (x) is graphed below. What is the average rate of change of the function f(x) on the interval - 1 ≤ x ≤ 3?
jonny [76]

Answer:

\displaystyle -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Average Rate of Change: \displaystyle \frac{f(b) - f(a)}{b - a}

Step-by-step explanation:

<u>Step 1: Define</u>

Interval -1 ≤ x ≤ 3

a = -1, b = 3

f(a) = f(-1) = 4

f(b) = f(3) = -4

<u>Step 2: Find Average</u>

  1. Substitute in variables [ARC]:                     \displaystyle \frac{f(3) - f(-1)}{3 + 1}
  2. Substitute:                                                   \displaystyle \frac{-4 - 4}{3 + 1}
  3. [Fraction] Subtract/Add:                             \displaystyle \frac{-8}{4}
  4. [Fraction] Divide:                                        \displaystyle -2
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2 years ago
Leigh bought a conical candle wax mold. The height of the mold is 16.2 inches and the radius of the inside of the top of the con
gavmur [86]

Answer:

C

the answer is C

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3 years ago
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