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AnnZ [28]
3 years ago
11

An airplane flies 240 km in 15 minutes. What is it's average speed in kilometers per hour?

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0
The answer is 960 kilometers per hour
slega [8]3 years ago
6 0

answer is 960 per hour

240 x 4=960

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dusya [7]

Answer:

The equation of the line will be:

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Step-by-step explanation:

Given the points

  • (0, 0)
  • (3, 0)

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\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(0,\:0\right),\:\left(x_2,\:y_2\right)=\left(3,\:0\right)

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We know that the value of y-intercept can be obtained by setting x=0, and solving for y

Here,

at x = 0, the value of y = 0

Thus,

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now substituting m = 0 and b = 0 in the slope-intercept form

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3 years ago
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mojhsa [17]
I- please ask a question. This is not a question
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3 years ago
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2 years ago
Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

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5) Substitute the values we already know

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6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

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Vilka [71]

Answer:

4/15 is your answer my friend

Step-by-step explanation:

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