I think that a linear equation can have no solution, one solution, or infinitely solutions. It just depends on what is the equation. That's what I think
Answer:
Hello! Your answer would be, A)F(x)=2x^2-8x-42
Step-by-step explanation:
Hope I helped! Brainiest plz!♥ Have a nice afternoon. Hope you make a 100%! -Amelia
STEP - BY - STEP EXPLANATION
What to find?
The the value of secθ.
Given:
(4, 3)
⇒(x, y) = (4, 3)
Step 1
Draw a sketch.
Step 2
Substitute the values into the trig. ratio formula below.
![tan\theta=\frac{opposite}{adjacent}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cfrac%7Bopposite%7D%7Badjacent%7D)
From the sketch above, opposite = 3 and adjacent = 4
![tan\theta=\frac{3}{4}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cfrac%7B3%7D%7B4%7D)
Step 3
Find the value of the hypotenuse side using Pythagoras theorem.
let h be the hypotenuse side.
![\begin{gathered} h^2=4^2+3^2 \\ \\ =16+9 \\ \\ =25 \\ \\ h=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D4%5E2%2B3%5E2%20%5C%5C%20%20%5C%5C%20%3D16%2B9%20%5C%5C%20%20%5C%5C%20%3D25%20%5C%5C%20%20%5C%5C%20h%3D5%20%5Cend%7Bgathered%7D)
Hence, hypotenuse = 5
Step 4
Substitute the values into the formula below:
![\begin{gathered} cos\theta=\frac{adjacent}{hypotenuse} \\ \\ =\frac{4}{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20cos%5Ctheta%3D%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%20%5C%5C%20%20%5C%5C%20%3D%5Cfrac%7B4%7D%7B5%7D%20%5Cend%7Bgathered%7D)
But,
![sec\theta=\frac{1}{cos\theta}=\frac{1}{\frac{4}{5}}=\frac{5}{4}](https://tex.z-dn.net/?f=sec%5Ctheta%3D%5Cfrac%7B1%7D%7Bcos%5Ctheta%7D%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cfrac%7B5%7D%7B4%7D)
ANSWER
secθ= 5/4
tanθ=3/4
Answer:
Combine like terms4ℎ+3ℎ+ℎ8ℎ
Solution8ℎ
Step-by-step explanation:
Answer: 4x^2 + 6xy + 2y^2
Step-by-step explanation:
(2x + y)(2x + 2y) =
2x*2x + 2x*2y + y*2x + y^2y =
4x^2 + 4xy + 2xy + 2y^2 =
4x^2 + 6xy + 2y^2