FOR THE FIRST PROBLEM:
Differentiating p^2 + 2q^2 = 1100 with respect to time => 2p(dp/dt) + 4q(dq/dt) = 0
<span>dp/dt = -2q/p(dq/dt) </span>
<span>R = pq </span>
<span>dR/dt = p(dq/dt) + q(dp/dt) = -p²/2q(dp/dt) + q(dp/dt) = (2q² - 1100)/2q * (dp/dt) + q(dp/dt) </span>
<span>A = (2q - 550/q)
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Hello!
Let's solve !
⇒ (x - 3)² = 5
⇒ x² - 6x + 9 = 5
⇒ x² - 6x + 4 = 0
⇒ x = -(-6) ± √36 - 4(1)(4) / 2
⇒ x = 6 ± √20 / 2 = 6 ± 2√5 / 2
⇒ x = 3 ± √5
∴ The solutions are x = 3 + √5 and x = 3 - √5.
Width-24 Length-29
Two sides of the rectangle are 5 cm bigger than the other two. So you would add the two 5 cm together (10cm). If you take the 10 cm off you (106-10) you will get a square. Then all you have to do is divide 96 by 4 (24), and add back on the two 5cm from the beginning to the length (29).
Step-by-step explanation:
If the parabola has the form
(vertex form)
then its vertex is located at the point (h, k). Therefore, the vertex of the parabola
is located at the point (8, 6).
To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is
where 
is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is
By definition, the length of the latus rectum is four times the focal length so therefore, its value is
