Answer:
The last answer 
Step-by-step explanation:

The formula to find it is 
so
is correct
A•B=C
A•B=-21
Find factors of 21 ( it doesn't matter that it's negative ) that at up to be 4
It's 7and 3
Then put x^2+7x+3x-21 and then factor by grouping
Do the same steps for #2
What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2
x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic
x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3
5x - 3 = 0
No it is not a quadratic because it does not have x^2
2x^2 + 12x = 0
Yes because there's x^2
5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2
9x^2 + 6x - 3 = 0
Yes because there's x^2
It can’t be a mixed number
The coefficient of 'y' in her simplified answer is 10.