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3 years ago

What two numbers can be multiplied together to equal 108, and added together to equal -17?

Mathematics

1 answer:

ankoles [38]3 years ago

7 0

<span>X x Y = 108 hope it helps</span>

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Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth

pav-90 [236]

Answer:

$\sqrt{13}$ units

Step-by-step explanation:

The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$ . Let $(x_1,y_1)\rightarrow(5,1)$ and $(x_2,y_2)\rightarrow(3,4)$ , thus:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}$

Therefore, the distance between points P(5,1) and Q(3,4) is $\sqrt{13}$ units.

8 0

2 years ago

Idk what two coplanor lines are

liq [111]

Coplanar lines are R, U, and V

4 0

3 years ago

Mya claims (m∠3 + m∠4) = m∠1

Lapatulllka [165]

Answer:

its answer b

Step-by-step explanation:

B:(m∠1 + m∠2) = 180° and (m∠3 + m∠4) = 180°

5 0

3 years ago

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po

grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm

Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

$=xy$

we are given that area as 1536

so, we can set it to 1536

$xy=1536$

now, we can solve for y

$y=\frac{1536}{x}$

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

$A=(8+x+8)\times (12+y+12)$

$A=(x+16)\times (y+24)$

now, we can plug back y

$A=(x+16)\times (\frac{1536}{x}+24)$

now, we have to minimize A

so, we will find derivative

$A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)$

we can use product rule

$A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

$=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

now, we can simplify it

$A'=-\frac{24576}{x^2}+24$

now, we can set it to 0

and then we can solve for x

$A'=-\frac{24576}{x^2}+24=0$

$-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2$

$-24576+24x^2=0$

$x=32,\:x=-32$

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

$x=32$

now, we can solve for y

$y=\frac{1536}{32}$

$y=48$

so, dimensions of printed poster are

length is 32 cm

width is 48 cm

5 0

3 years ago

Plz answer for a brainly, ill give u brainliy and 100 points

bezimeni [28]

Answer:

what is this

Step-by-step explanation:

what's the question

5 0

3 years ago

Read 2 more answers