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tangare [24]
3 years ago
7

What is the solution to the system of equations? y = –3x – 2 5x + 2y = 15 (–40, 19) (–19, 55) (19, –40) (55, –19)

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0

Step-by-step Answer:

What is the solution to the system of equations?

y = –3x – 2 ..............(1)

5x + 2y = 15..............(2)

Substitute (1) in (2) to give

5x + 2(-3x-2) = 15

5x-6x-4 = 15

-x-4=15

solve for x:

-4-15 = x

x=-19

Now substitute x=-19 into equation (1)

y = -3x-2 = 57-2 = 55

Therefore the solution is (-19, 55)

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Solve 4.62 + (−12.3).<br><br> 56.83<br> 5.85<br> −7.68<br> −16.92
ikadub [295]

The sum of the given decimal numbers is -7.68

<h3>Sum of decimal numbers</h3>

Decimal numbers are numbers that contains decimal points. Given the expression below;

4.62 + (−12.3).

Convert to fraction to have:

4.62 + (−12.3) = 462/100 - 123/10

Find the LCM

4.62 + (−12.3) = 462-1230/100

4.62 + (−12.3) = -768/100

4.62 + (−12.3) =-7.68

Hence the sum of the given decimal numbers is -7.68

Learn more on sum of numbers here; brainly.com/question/25734188

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4 0
1 year ago
Solve y=-3x² + 4.5x – 20<br> Use the Quadratic formula
statuscvo [17]

Answer:

x=0.75 \pm 2.47067i

Step-by-step explanation:

Quadratic Formula: x=\frac{-b \pm \sqrt{b^2-4ac} }{2a}

√-1 is imaginary number i

Step 1: Define

y = -3x² + 4.5x - 20

a = -3

b = 4.5

c = -20

Step 2: Substitute and Evaluate

x=\frac{-4.5 \pm \sqrt{4.5^2-4(-3)(-20)} }{2(-3)}

x=\frac{-4.5 \pm \sqrt{20.25-240} }{-6}

x=\frac{-4.5 \pm \sqrt{-219.75} }{-6}

x=\frac{-4.5 \pm \sqrt{219.75}(\sqrt{-1} ) }{-6}

x=\frac{-4.5 \pm i\sqrt{219.75} }{-6}

x=\frac{4.5 \pm i14.824 }{6}

x=0.75 \pm 2.47067i

7 0
3 years ago
Solution of the equation<br> 3x/5+1=4x/15+7
Anika [276]

Answer:

x = 18

Step-by-step explanation:

Given

\frac{3x}{5} + 1 = \frac{4x}{15} + 7 ( subtract 1 from both sides )

\frac{3x}{5} = \frac{4x}{15} + 6

Multiply through by 15 to clear the fractions

9x = 4x + 90 ( subtract 4x from both sides )

5x = 90 ( divide both sides by 5 )

x = 18

4 0
3 years ago
Help me find x on either one of these problems please!
mash [69]
In the problem with the white circle, x=100, in the problem with the blue circle, x might equal 165, but I'm not entirely certain.  But I am certain about the first one.
3 0
3 years ago
In the figure, PQ is parallel to RS. The legth of RP is 4 cm; the length of PT is 16 cm; the length of QT is 20 cm. What is the
Studentka2010 [4]
4/16  = SQ/20

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6 0
3 years ago
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