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belka [17]
3 years ago
11

What would the total bill be of a lunch that cost &7.99 with a tax rate of 7%

Mathematics
1 answer:
Nana76 [90]3 years ago
5 0
Hello Basketballlover28,

Answer:

Price: $ 7.99

Sales Tax (7%): $ 0.56

Total: $ 8.55
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Write the ordered pair that represents YZ. Then find the magnitude of YZ. y(-4,12), Z(1,19).
ki77a [65]

The magnitude of YZ is 8.6

<u>Explanation:</u>

<u />

Y( -4, 12)

Z ( 1, 19)

Magnitude of YZ = ?

We know:

YZ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

On substituting the value we get:

YZ = \sqrt{(1+4)^2 + (19 - 12)^2} \\\\YZ = \sqrt{(5)^2 + (7)^2} \\\\YZ = \sqrt{25+49} \\\\YZ = \sqrt{74} \\\\YZ = 8.6

Thus, the magnitude of YZ is 8.6

6 0
3 years ago
Read 2 more answers
While hiking, Sanjay went up 200 meters. If Sanjay started at 500 meters above sea level, which integers represents his elevatio
Aliun [14]

Answer:300

Step-by-step explanation:

-200+500=300

3 0
3 years ago
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nataly862011 [7]

Answer:

15 feet

Step-by-step explanation:

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6 0
3 years ago
Billy has 1 gallon of paint. He is going to pour it into a paint tray that measures 10 inches wide, 14 inches long, and 4 cm dee
V125BC [204]

Answer:

The paint will not fill the tray by 10.53 cubic inches.

Step-by-step explanation:

We will find the volume of the paint tray and compare it with the volume of the gallon.

Given dimensions are:

Length = 14 inches

Width = 10 inches

Depth = 4 cm or \frac{4}{2.54}=1.575 inches

The volume is given by = length x width x depth

Volume = 14\times10\times1.575=220.50 cubic inches

Volume of 1 gallon is given as = 231 cubic inches

We can see that volume of 1 gallon is more than volume of tray.

Difference = 231-220.50=10.5 cubic inches.

So, the paint will not fill the tray by 10.53 cubic inches.

3 0
2 years ago
A game of chance involves rolling an unevenly balanced 4-sided die. The probability that a roll comes up 1 is 0.21, the probabil
WITCHER [35]

Answer:

2.65 dollars

Step-by-step explanation:

The expected value for a discrete variable is calculated as:

E(x)=x1P(x1) + x2P(x2) + ... + xnP(xn)

Where x1, x2, ... , xn are the possibles values of the variable and P(x1), P(x2), ... , P(xn) are the probabilities of x1, x2, ... , xn respectively.

In this case, the roll can comes up 1, 2, 3 or 4 and you can win 1, 2, 3 or 4 dollars respectively. So, taking into account that they are mutually exclusive events, the probability that the player win 1, 2, 3 or 4 dollars is:

P(1) = 0.21

P(2) = P(1∪2) - P(1) = 0.42 - 0.21 = 0.21

P(3) = P(2∪3) - P(2) = 0.51 - 0.21 = 0.3

P(4) = 1 - P(1) - P(2) - P(3) = 1 - 0.21 - 0.21 - 0.3 = 0.28

Therefore, If you win the amount that appears on the die the expected winning are:

E(x) = $1P(1) + $2P(2) + $3P(3) + $4P(4)

E(x) = $1(0.21) + $2(0.21) + $3(0.3) + $4(0.28)

E(x) = $2.65

4 0
3 years ago
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