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Nesterboy [21]
2 years ago
5

What is 12 times 21 ? Plz hurry amanda

Mathematics
2 answers:
netineya [11]2 years ago
8 0
252 is the answer you would be looking for.

kykrilka [37]2 years ago
4 0
It is 252. hope I helped!
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A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCI/L of radon. The resulting reading
valkas [14]

Answer:

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

p_v =2*P(t_{11}  

Step-by-step explanation:

1) Data given and notation  

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

The results obtained are:

\bar X=98.375 represent the sample mean  

s=0.6.109 represent the sample standard deviation  

n=12 sample size  

\mu_o =100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :  

Null hypothesis:\mu = 100  

Alternative hypothesis:\mu \neq 100  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921  

4) P-value  

First we need to find the degrees of freedom for the statistic given by:

df=n-1=12-1=11

Since is a two sided test the p value would given by:  

p_v =2*P(t_{11}  

5) Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.  

3 0
3 years ago
Write the algebraic expression of “the sum of a multiple of 3 and the number one greater than multiple of 3”
marysya [2.9K]

Answer:

9 IS THE ANSWER

Step-by-step explanation:

3*3=9

6 0
2 years ago
Please help me It’ll help a lot
Digiron [165]

Answer:

heyy

the answers "20"

Step-by-step explanation:

Okay using the x that we have we find 40 and plug that into the graph and we have 20 :p

7 0
2 years ago
Val walks 2 3/5 miles each day . Bill returns 10 miles once every 4 days . In 4 days, who covers the greatest distance
julia-pushkina [17]
Val by 4/10 walk longer
7 0
2 years ago
If the average mass of a peacock is 4.95 kilograms, what is the average mass of a peacock In grams?
anyanavicka [17]

Answer:

4950g

Step-by-step explanation:

firstly remember the formula for converting from kg to g

Kilograms ( kg) to grams(g)

1 kg = 1000g

therefore to convert 4.95 kg to g

is 4.95 * 1000

=<u> 4950g</u>

6 0
3 years ago
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