Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
<span>The end product of the radioactive decay of uranium is a non-radioactive lead isotope.
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The correct answer is (a.) liver. The liver contains the tubules with sinusoids which is lined with macrophages that leads to the central venous structure. A liver is a vital organ that serves as a gland that plays an important role in animal's and vertebrae's metabolism.
Answer:
i believe a punnett square would do that
Explanation:
Answer:
C is surely the answer
C. Disrupting intermediate filaments will result in cells that are more susceptible to mechanical forces. In the case of the keratinocytes, disrupting keratin, a key IF in these cells, would result in very fragile cells. Less force would need to be applied using the magnetic beads to damage them or change their shape.
