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vivado [14]
3 years ago
10

Anyoneeee there?please help.Im desperate​

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:

B sas

Step-by-step explanation:

states that if two sides and the included angle of one triangle arecongruent 

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300000cm in meteres then in km
Vadim26 [7]

Answer:3

Step-by-step explanation:because from cm to km you have to divide by 100,000 to get km from cm so 300,000/100,000=3

3 0
3 years ago
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The weight of a mandarin orange is about 6 ounces. A basket that weighs 4 ounces will hold m mandarin oranges, the total weight
trasher [3.6K]

Answer:

4 + 6m = 70

Step-by-step explanation:

4 is the basket

6m is the total weight of mandarins

70 is total weight

7 0
3 years ago
Which is the best definition of a counterexample?
Leni [432]

Answer:

D. An example that shows a statement is not true.

Step-by-step explanation:

3 0
2 years ago
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A recipe calls for 14cup of brown sugar for every 23cup of white sugar. How many cups of brown sugar are required for every cup
photoshop1234 [79]

Note: Consider all the numeric values are in the fraction form. Like 14\to \dfrac{1}{4}, 23\to \dfrac{2}{3} etc.

Given:

A recipe calls for \dfrac{1}{4} cup of brown sugar for every \dfrac{2}{3} cup of white sugar.

To find:

The number of cups of brown sugar that are required for every cup of white sugar.

Solution:

We know that,

Required brown sugar for \dfrac{2}{3} cup of white sugar =  \dfrac{1}{4} cup

Using this, we get

Required brown sugar for 1 cup of white sugar =  \dfrac{\dfrac{1}{4}}{\dfrac{2}{3}} cup

                                                                              =\dfrac{1}{4}\times \dfrac{3}{2} cup

                                                                              =\dfrac{3}{8} cup

So, \dfrac{3}{8} cup of brown sugar is required for every cup of white sugar.

Therefore, the correct option is B.

6 0
2 years ago
Solve for x in the equation:log6-2logx=1.4​
Annette [7]

9514 1404 393

Answer:

  x = (√6)/10^0.7 ≈ 0.488737

Step-by-step explanation:

It can work reasonably well to take antilogs first.

  \log(6)-2\log(x)=1.4\\\\\dfrac{6}{x^2}=10^{1.4}\\\\\dfrac{6}{10^{1.4}}=x^2\\\\x=\dfrac{\sqrt{6}}{10^{0.7}}\approx0.488737

7 0
2 years ago
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