The point is anywhere below 0 on the Y axis
X2 + y2 = 29
Center of the circle
x=0 and y=0
Therefore the slope of the line perpendicular to the tangent line
(y2-y1) / (x2-x1)
(5-0) / (2-0)
5/2
so the slope of the tangent
-2/5
General equation for the line
y = mx + c
if the line satisfies with the point (2,5)
5 = 2m + c
m = -2/5
5 = 2 * (-2/5) + c
c = 5 + (4/5)
c = 29/5
Therefore the equation of the line
y = mx + c
y = (-2/5) m + 29/5
Answer:
y = -1/2x
Step-by-step explanation:
Okay, so you probably heard of the slope-intercept form, y = mx + b. We have to use that formula to create a line that goes through (2,1), because thats the bisector.
Let's have our point start at the origin, (0,0). This you make our equation of y=mx+b <u>into</u> y = mx + 0. Since it's 0, let's just <em>drop</em> it out of our equation.
So now for slope. Rise/Run is what we're going to use to create our slope. Since we started at the origin, our slope is going to be negative. We can go down one over two from the origin to get to points (2,1) so why can't that be our slope? We're rising -1, and running 2, making our slope -1/2. In the equation, it would be y= -1/2x + 0, which can be simplified into y = -1/2x
It's a lot of writing and explaining, so I hope this helps! Try asking your teacher just to make sure it's correct.
The answer would be n= -66/19
Answer:
Step-by-step explanation:
Vertex: ( -2, -25)
Axis of symmetry: -2
