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Finger [1]
3 years ago
5

Given: x + y = 10. If x = -21, what is y? 011 0-31 31

Mathematics
1 answer:
stepladder [879]3 years ago
3 0

Answer:

31

Step-by-step explanation:

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HELLPPPP HELPPP PLEASEE
kvv77 [185]

Answer:

| 4x - 6 | = - 6

Step-by-step explanation:

The absolute value function always produces a positive value.

| 4x - 6 | = - 6 ← negative value is not possible

5 0
3 years ago
Read 2 more answers
. Two friends pooled the tickets they won from playing video games to get a prize that requires 500 tickets. If one friend won 8
kupik [55]

Answer:

Friend 1 (with 80 more tickets) gets 290

Friend 2 gets 210

Step-by-step explanation:

500-80 = 420 tickets |

^in order to figure out how many total tickets they got without the 80 extra

420/2 = 210 |

^divide by 2 to figure out how many tickets each friend had

210+80 |

^add 80 to figure out how many tickets friend one gets

<u>210</u><u> </u><u>+</u><u> </u><u>290</u><u> </u><u>=</u><u> </u><u>500</u>

7 0
3 years ago
Pls help :( (will get reported if link)
ruslelena [56]

Answer:

Step-by-step explanation:

4 0
3 years ago
Find the area and perimeter of the following triangle with the given vertices:
Vaselesa [24]
Find the area and perimeter of the following triangle with the given vertices:
(1, 2), (8, 2) and (3, 6)
Explain your reasoning; show all your work for full credit!

7 0
4 years ago
A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th
baherus [9]

Answer:

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.553, n = 10

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039

P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219

P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724

P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0
3 years ago
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