What are the domain and range of the function?

What is the median of the data set represented by the dot plot?

umka21 [38]

Answer:

The median is 5.

Step-by-step explanation:

To find the median you have to do steps, (they are really easy):

The median is like the middle of the graph so just try finding the middle, ( i could explain this in a different way but it's hard to explain) Hope this helps.

3 0

3 years ago

Read 2 more answers

When solving for -1/5(x-25)=7 what is the correct sequence of operations

slamgirl [31]

A sequence of operations that will get you to the solution is ...

... d. multiply each side by-5, add 25 to each side

_____

That is not the only correct sequence of operations. However the other ones listed here are incorrect ways to get to x = -10.

You can do whatever multiplication and addition you like to each side of the equation, but if those operations are poorly chosen, they will make finding the solution more difficult.

4 0

3 years ago

Jake performed an experiment to find out which type of chocolate melts the fastest, milk chocolate or dark chocolate. He tested

lutik1710 [3]

Answer:

Please see attached image for full question

"After 64 seconds, ABOUT HALF of the brands of milk chocolate are LIKELY to melt and NONE of the brands of Dark Chocolate are likely to melt"

Step-by-step explanation:

The right answer is

"After 64 seconds, ABOUT HALF of the brands of milk chocolate are LIKELY to melt and NONE of the brands of Dark Chocolate are likely to melt"

We can easily check this solution by seeing the time it took for each chocolate to melt in the attached picture.

After 64 seconds have passed, half of the brands of milk chocolate had already melted, but the dark chocolate time starts after 200s

4 0

3 years ago

Please Help - Suppose f(t)=6t−8−−−−√.

Gnoma [55]

$(a)\\\\\\\text{Given that,}~~\\\\ f(t) =\dfrac 6{\sqrt{t-8}}\\\\\\\\\implies f'(t) = 6\left[\dfrac{\left(\sqrt{t-8}\right) \cdot 0 - \dfrac 1{2\sqrt{t-8 }}}{\left(\sqrt{t-8}\right)^2}\right]\\\\\\\\\implies f'(t) = -6\left(\dfrac {\dfrac 1{2\sqrt{t-8}}}{t-8}\right)\\\\\\\implies f'(t) = -6\left(\dfrac{1}{2\sqrt{t-8} (t-8)}\right)\\\\\\\implies f'(t) =-\dfrac 3{(t-8)^{\tfrac 32}}$

(b)

$\text{Given that,}\\\\y=f(t)\\\\\text{Slope of y,} ~~ f'(t) =-\dfrac 3{(t-8)^{\tfrac 32}}\\\\\text{At point (33, 6/5)}\\\\\\f'(t) = -\dfrac 3{(33-8)^{\tfrac 32}} = - \dfrac 3{ (25)^{ \tfrac 32}} = - \dfrac 3{5^3} = -\dfrac 3{125}\\\\\\\text{Equation with given points,}\\\\y - \dfrac 65 = -\dfrac 3{125} ( t - 33)\\\\\\\implies y =-\dfrac 3{125} t +\dfrac{99}{125} + \dfrac 65\\\\\\\implies y = -\dfrac 3{125} t +\dfrac{249}{125}$

8 0

2 years ago

X^2+1/x^2=18 find x-1/x

MAVERICK [17]

Notice that

$\left(x-\dfrac1x\right)^2=x^2-2+\dfrac1{x^2}=18-2=16$

which tells us

$x-\dfrac1x=\pm4$

4 0

3 years ago