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horsena [70]
3 years ago
14

PLEASE HELP IM FAILING ALGEBRA!!(answer all 3 problems) (SHOW WORK)

Mathematics
1 answer:
Lena [83]3 years ago
5 0

Hope this helps You ;)

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Here is a question for all :)
Schach [20]

Answer:

The circle on the far left is the sum of 4x + 3y and 2x - y so the answer is 4x + 3y + 2x - y = 6x + 2y. The circle on the far left is the sum of x + 4y and something. To find that "something" we can do 4x + 5y - (x + 4y) = 3x + y which is the value of the bottom right rectangle. This means that the value of the bottom circle is 2x - y + 3x + y = 5x.

5 0
3 years ago
Read 2 more answers
In a file of 10 records with 2 errors, 5 are examined. Let the random variable be the number of errors.​
emmasim [6.3K]
Jasjjhahahahwhwjwjwjwj
8 0
3 years ago
418, 832 in expanded form
castortr0y [4]
Expanded form pretty much means that you break down every digit into an addition phrase. So, for 418,832, that would mean:
4 1 8 8 3 2
400000 10000 8000 800 30 2
400000+10000+8000+800+30+2
4 0
3 years ago
Read 2 more answers
The eleventh term from the end of the AP 14, 19, 24, …………., 264 is
vazorg [7]

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

6 0
4 years ago
(57x2:3)+32x450-[39-(4+2):2[+8=
tigry1 [53]

Answer:

57×2/3+32×450-[39-4+2]/2+8

57×2/3+32×450-(39-6/2)+8

57×2/3+32×450-36+8

57×2/3+14400-28

57×2/3+14372

38+14372

14410

8 0
2 years ago
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