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2 years ago

6

What are the solutions to the system of the equations graphed below?

2 answers:

xz_007 [3.2K]2 years ago

8 0

A (2,0) and (0,-8) because it’s shown in the picture that’s the red line indicates the place it needs to be in

Zigmanuir [339]2 years ago

4 0

Answer:

D

Step-by-step explanation:

Where the graphs intersect each other is where the solution is. The graphs intersect each other at the points (0,-8) and (4,8). Hope this helps!

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Solve using the quadratic formula:20\x+10\(x-10)=10\3

Masja [62]

Answer : x= 15 , 4

steps by step solution : plz see in attachment ✌

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3 years ago

A train goes twice as fast downhill as it can go uphill, and 2/3 feet as fast uphill as it can go on level ground. If it goes 12

Yuri [45]

Answer:

0.5hrs

Step-by-step explanation:

Let the speed downhill be $x$ ,

Speed uphill is $0.5x$ . We are told than speed uphill is $\frac{2}{3}$ the speed on flat ground. Therefore the speed on level ground will be $\frac{0.5x}{2/3}=0.75x$ .

From this info, we can obtain the actual speed, $v_g$ on level ground as:

$x=120m/h\\0.75x=v_g\\\\\therefore v_g=\frac{0.75x \times 120m/h}{x}\\v_g=90m/h$

speed, distance and time have the relation $s=d/t$ so to obtain time to cover 45miles:

$t=d/s\\=45/90\\=0.5h$

Hence it takes 0.5hrs to cover 45miles on flat ground.

4 0

3 years ago

X2 + y<br> when x = -2 and y = 3.

OlgaM077 [116]

(-2)2+3= -1 hope this helps you

6 0

2 years ago

Read 2 more answers

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3 years ago

Read 2 more answers

Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.

evablogger [386]

Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) $(5^2)(5^3)$

As we know that

$a^m\times a^n=a^{m+n}$

So, it becomes,

$5^2\times 5^3=5^{2+3}=5^6=15625$

(b) $(5^2)(5^{-3})$

So, it becomes,

$5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2$

(c) $(5^2)^2$

As we know that

$(a^m)^n=a^{mn}$

So, it becomes,

$5^{2\times 2}=5^4=625$

(d) $5^{-3}$

$a^{-m}=\dfrac{1}{a^m}\\\\5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}=0.008$

Hence, a) 15625, b) 0.2, c) 625, d) 0.008.

4 0

3 years ago