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s2008m [1.1K]
3 years ago
6

What two numbers multiple to equal 16 but add up to equal -17​

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

-16 and -1

Step-by-step explanation:

-16 *-1 = 16

-16+-1=-17

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HELP WILL GIVE BRAINLIEST
QveST [7]

Answer:

(-8,1)

Step-by-step explanation:

7 0
3 years ago
Which product is negative?
BigorU [14]

Answer:

the first one is negative

Step-by-step explanation:

1= -168

2= 360

3= 0

4= 360

a negative times a negative is a positive, 1 has 3 negatives tho so its gonna be a negative. 3 would be the other one but it has a zero making the answer 0

4 0
3 years ago
Suppose y varies directly as x, and y=14 when x=4. What is the value of y when x=9
Katena32 [7]

Given :-

  • y varies directly as x, and y=14 when x=4.

To Find :-

  • the value of y when x=9 .

Solution :-

<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>,</u>

  • y = kx ( k is constant )

<u>When</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>,</u>

  • 14 = k(4)
  • k = 14/4
  • k = 7/2

<u>W</u><u>h</u><u>e</u><u>n</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>,</u>

  • y = 7/2*9
  • y = 63/2
  • y = 31.5
8 0
2 years ago
Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
2 years ago
Three boxes of supplies have an average (arithmetic mean) weight of 7 kilograms and a median weight of 9 kilograms. What is the
GuDViN [60]

Answer:

3

Step-by-step explanation:

A) 1

(B) 2

(C) 3

(D) 4

(E) 5

Mean is a measure of central tendency. It is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number

Mean = sum of numbers / number of observation

sum of numbers = 3 x 7 = 21

Median is the number that is at the center or middle of a set of obervations

x +  9+ y = 21

x= lowest number

y = highest number

x + y = 21 - 9

x + y = 12

If x = 1 y = 11

if x = 2 y = 10

if x = 3 y = 9

if x = 4 y = 8

the first 3 are plausible and the median would still be 9 if x = 4, median would be 8

3 0
2 years ago
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