All categories

3 years ago

What two numbers multiple to equal 16 but add up to equal -17

Mathematics

1 answer:

ELEN [110]3 years ago

5 0

Answer:

-16 and -1

Step-by-step explanation:

-16 *-1 = 16

-16+-1=-17

You might be interested in

HELP WILL GIVE BRAINLIEST

QveST [7]

Answer:

(-8,1)

Step-by-step explanation:

7 0

3 years ago

Which product is negative?

BigorU [14]

Answer:

the first one is negative

Step-by-step explanation:

1= -168

2= 360

3= 0

4= 360

a negative times a negative is a positive, 1 has 3 negatives tho so its gonna be a negative. 3 would be the other one but it has a zero making the answer 0

4 0

3 years ago

Suppose y varies directly as x, and y=14 when x=4. What is the value of y when x=9

Katena32 [7]

Given :-

y varies directly as x, and y=14 when x=4.

To Find :-

the value of y when x=9 .

Solution :-

According to Question ,

y = kx ( k is constant )

When y = 14 and x = 4 ,

14 = k(4)
k = 14/4
k = 7/2

When x = 9 ,

y = 7/2*9
y = 63/2
y = 31.5

8 0

2 years ago

Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r

erastova [34]

Answer:

The probability is $\frac{56!}{64!}$

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, $64 \choose 8 .$

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function $f : A \rightarrow A ,$ with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

$\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}$

7 0

2 years ago

Three boxes of supplies have an average (arithmetic mean) weight of 7 kilograms and a median weight of 9 kilograms. What is the

GuDViN [60]

Answer:

Step-by-step explanation:

A) 1

(B) 2

(D) 4

(E) 5

Mean is a measure of central tendency. It is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number

Mean = sum of numbers / number of observation

sum of numbers = 3 x 7 = 21

Median is the number that is at the center or middle of a set of obervations

x + 9+ y = 21

x= lowest number

y = highest number

x + y = 21 - 9

x + y = 12

If x = 1 y = 11

if x = 2 y = 10

if x = 3 y = 9

if x = 4 y = 8

the first 3 are plausible and the median would still be 9 if x = 4, median would be 8

3 0

2 years ago

What two numbers multiple to equal 16 but add up to equal -17​

What two numbers multiple to equal 16 but add up to equal -17