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Svetach [21]
2 years ago
14

Natalie Albert deposited checks totaling $1,735,97 into her savings account. She withdrew $100.00 while

Mathematics
1 answer:
givi [52]2 years ago
7 0
Anything withdrawn you subtract. Then, you know the total and you know what you had. Subtract total from what you had and you will see the change.

1735.97-100=1635.97

1668.71-1635.97=32.74



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In a group of 60 students, 12 students take algebra one, 18 students take algebra 2 and 8 students take both subjects how many s
hoa [83]
60-12-18-2-8=20
=48-18-2-8
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So, 20 students don't take either of these subjects.
5 0
3 years ago
How to turn an a equation from standard form into vertex form
alekssr [168]

Is this a real question?

6 0
3 years ago
There were 100 pizzas sold at Romeo's Pizzeria on Tuesday. A large pizza costs $16 and a small pizza costs $11. If $1,550 worth
Blizzard [7]

Answer:

  • 10 small pizzas sold

Step-by-step explanation:

Let number of large pizzas be l and number of small be s.

<u>Then we have equations:</u>

  • l + s = 100
  • 16l + 11s = 1550

<u>From the first equation, we get l = 100 - s and substitute in the second equation:</u>

  • 16(100 - s) + 11s = 1550
  • 1600 - 16s + 11s = 1550
  • 5s = 1600 - 1550
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Number of small pizzas is 10

7 0
3 years ago
HELP PRECALC DO NOT UNDERSTAND WILL GIVE BRAINLIEST
Olegator [25]

Answer:

  the lower right matrix is the third correct choice

Step-by-step explanation:

Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).

Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.

__

We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.

The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...

  \left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]

Already, we see that the second row matches that in the lower right matrix.

The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.

The correct choices here are the two you have selected, and <em>the lower right matrix</em>.

3 0
3 years ago
Please show your work, tysm :D<br><br> ~giving brainliest!~
N76 [4]

Answer:

. 0625

Step-by-step explanation:

1/2^4

or

1/16

just doing half life

5 0
2 years ago
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