Using implicit differentiation, it is found that the radius is increasing at a rate of 0.0081 cm per minute.
<h3>What is the volume of a sphere?</h3>
The volume of a sphere of radius r is given by:

Applying implicit differentiation, the rate of change is given by:

In this problem, we have that:

Hence the rate of change of the radius is given as follows:




The radius is increasing at a rate of 0.0081 cm per minute.
More can be learned about implicit differentiation at brainly.com/question/25608353
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Answer: My best answer would be independent
Step-by-step explanation: because you would be the one rolling the dice but you don't know what it would be landing on
3 9/10 + 4/5
39/10 + 4/5
39/10 + 8/10
47/10= 4 7/10
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
Both equations are the same
<span>y=−4x+4 ----> y+4x=4,
so </span><span>consistent dependent</span>