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Strike441 [17]
3 years ago
15

The first term of an arithmetic sequence is 4 and the tenth term is 67.

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer:

Step-by-step explanation:

Formula

tn = a1 + (n-1)* d

Givens

tn = 67 (it is the last term or the nth term

n = 10

a1 = 4

find d

Solution

67 = 4 + (10 - 1)*d

67 = 4 + 9*d               Subtract 4 from both sides

67 - 4 = 9d            

63 = 9d                      Divide by 9

63/9 = 9d/9              

7  = d

Remark: This is a fundamental application of the arithmetic sequence. You pretty much have to know how to juggle it's parts.

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solve for y

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6 0
3 years ago
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Lunna [17]

Answer:

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Step-by-step explanation:

Given

x² - 6x + 9

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3 years ago
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4 years ago
5.<br> Evaluate f(x) = -2x2 -4 for x = 3.<br> O -10<br> O -18<br> 10<br> -22
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Answer:

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