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Strike441 [17]
2 years ago
15

The first term of an arithmetic sequence is 4 and the tenth term is 67.

Mathematics
1 answer:
Dmitry [639]2 years ago
6 0

Answer:

Step-by-step explanation:

Formula

tn = a1 + (n-1)* d

Givens

tn = 67 (it is the last term or the nth term

n = 10

a1 = 4

find d

Solution

67 = 4 + (10 - 1)*d

67 = 4 + 9*d               Subtract 4 from both sides

67 - 4 = 9d            

63 = 9d                      Divide by 9

63/9 = 9d/9              

7  = d

Remark: This is a fundamental application of the arithmetic sequence. You pretty much have to know how to juggle it's parts.

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The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

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3 years ago
Michel runs 6 miles in 50 minutes.<br>At the same rate , how many miles would he run in 35 minutes
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Range,median,mode <br> Will give Brainliest!!^^^^
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Answer:

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The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given
Rom4ik [11]

f'(x)\ge0 for all x in [-3, 0], so f(x) is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at x=-3.

From the plot, it's clear that on [-3, 0] we have f'(x)=-x. So

f(x)=\displaystyle\int(-x)\,\mathrm dx=-\dfrac{x^2}2+C

for some constant C. Given that f(0)=7, we find that

7=-\dfrac{0^2}2+C\implies C=7

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f(x)=-\dfrac{x^2}2+7

and

f(-3)=\dfrac52=2.5

5 0
3 years ago
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