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son4ous [18]
2 years ago
11

Evaluate ∫ e3x cosh 2x dx A.1/ e5x+1/ex+C 10 2 B. 1/ e3x + 1/ x + C 42 C. 1/ e5x + 1/ 10 5 x + C D. 1/ e5x + 1/ ex + C 22

Mathematics
1 answer:
Irina18 [472]2 years ago
3 0
Sh(2x) = (e^2x + e^-2x)/2 

<span>Thus the integral becomes </span>

<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>

<span>= e^5x/10 + e^x/2 + C 
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
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MariettaO [177]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;

\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}

\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}

\qquad \sf  \dashrightarrow  \:m =  - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)

\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~

\qquad \sf  \dashrightarrow \:y =  - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :

\qquad \sf  \dashrightarrow \:y <  - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0
2 years ago
Anwser: <br> 36÷(1-9×1-4)+1+2
kkurt [141]
So this is a BIDMAS question so first you do what’s in the brackets so you have (1-9x1-4) and you have to do the multiplication first out of that to get (1-9-4) which is -12 so then you have overall 36 / -12 + 1 + 2 so you have to do the division first so do 36/-12 to get -3 and you have -3 + 1 + 2 which is 0 so your answer is 0.
5 0
2 years ago
Read 2 more answers
The average Math SAT score of all incoming freshman at a large university is 490. A simple random sample of 200 of these incomin
nika2105 [10]

Answer:

Which is the output of the formula =AND(12>6;6>3;3>9)?

A.

TRUE

B.

FALSE

C.

12

D.

9

Step-by-step explanation:

4 0
3 years ago
How to convert To prepare for a bake-off, Louise used 0.61 kilogram of flour each day for 3 weeks. How many grams did Louise use
Ronch [10]

Given:

Louise used 0.61 kilogram of flour each day for 3 weeks.

To find:

How many grams did Louise use in those 3 weeks?

Solution:

We know that,

1 kg = 1000 g

Flour used by Louise each day for 3 weeks = 0.61 kg

1 week = 7 days

3 week = 21 days

Flour used by Louise for 3 weeks (21 days) = (21 × 0.61) kg

                                                                        = 12.81 kg

                                                                        = (12.81 × 1000)    [ 1 kg = 1000 g]

                                                                        = 12810 g

Therefore, flour used by Louise for those 3 weeks is 12,810 grams.

7 0
2 years ago
Please explain step by step
Lorico [155]

Answer:

Line PQ

Step-by-step explanation:

diameter: straight line that passes through the centre of the circle (point O), and runs from on side of the circle to the other end (from point P to point Q)

5 0
2 years ago
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