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son4ous [18]
3 years ago
11

Evaluate ∫ e3x cosh 2x dx A.1/ e5x+1/ex+C 10 2 B. 1/ e3x + 1/ x + C 42 C. 1/ e5x + 1/ 10 5 x + C D. 1/ e5x + 1/ ex + C 22

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0
Sh(2x) = (e^2x + e^-2x)/2 

<span>Thus the integral becomes </span>

<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>

<span>= e^5x/10 + e^x/2 + C 
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
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