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Andre45 [30]
3 years ago
14

Which system of equations has the same solution as the system below? 3x+3y=8 and 2x-y=5

Mathematics
2 answers:
Nata [24]3 years ago
8 0

Answer:

<h2>B. 3x+3y=8 4x-2y=10 </h2>

Step-by-step explanation:

The choices for this question are

A. 3x+3y=8 4x-2y=5

B. 3x+3y=8 4x-2y=10

C. x+y=8 2x-y=5

D. 9s+9y=22 18x+9y=45

Among the options, the system that has the same solutions than the given system is B., because as you can observe such system has the same equations, the first one is the same equation 3x+3y=8, and the second one is the same equation with a factor applied, if we divide such equation by two, we would have

\frac{4x-2y}{2} =\frac{10}{2}\\ 2x-y=5

As you can observe, we get the same second equation that it's included in the given system

So, we can conclude that the system B, and the given system are the same, therefore they have the same solutions.

skad [1K]3 years ago
4 0
3x+3y=8                     2x-y=5

y=-x+8/3                    y=2x-5




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Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

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The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

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