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Leya [2.2K]
2 years ago
14

The shape is composed of squares and quarter circles. Select all the expressions that represent its perimeter. (Select all that

apply.) 42+14 7+7+7+7+7+7+3.5+3.5+3.5+3.5 91+14 147+49 7+7+7+7+7+7+7+7+7+7
Mathematics
2 answers:
Bezzdna [24]2 years ago
7 0

Answer:

The other guy who answered this is wrong

Step-by-step explanation:

Your welcome

Phantasy [73]2 years ago
6 0

Answer:

91+14π

Step-by-step explanation:

The question is incomplete. Find the complete question attached.

From the diagram shown;

It contains 4 quarter circles which is equal to a circle.

Perimeter of a circle = 2πr

r is the radius = length of one side of the square =7

Perimeter of the circle = 2πr

Perimeter of the circle = 2π(7)

Perimeter of the 4 quarter circles = 14π

Also in the diagram, there are 13 sides of the square present.

Perimeter of the squares = 13×length of one side of the square (Sum of all the sides)

Perimeter of the squares = 13×7 =91

Perimeter of the figure = Perimeter of the 4 quarter circles + Perimeter of the squares

Perimeter of the figure = 91+14π

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The height of a trapezoid is 16in. The bases are 32in and 24in. What is the area of the trapezoid.
oksano4ka [1.4K]

Answer:

448in^2

Step-by-step explanation:

The area of a trapezoid is the bases added divided by two times the height.

(32+24)/2*16=28*16=448 in^2

4 0
3 years ago
Find the slope from the table:
Aleonysh [2.5K]

Answer:

B! \frac{-5}{3}

Step-by-step explanation:

Because 10 minus 5 (from the y column) is -5. And -5 - (-2) is +3. So you get -5 over 3 (\frac{-5}{3}). which is B!

Can you give me brainliest please?? :)

5 0
2 years ago
I need help with this question:(
vivado [14]
The answer is 8^18...
3*6 = 17 and the 8 stays the same
5 0
3 years ago
A​ half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of​
Ainat [17]

Answer:

99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of​ today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of​ today's women in their 20's have been taken.

<u><em /></u>

<u><em>Let </em></u>\bar X<u><em> = sample mean heights</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean height of women = 64.7 inches

            \sigma = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches is given by = P(\bar X \geq 65.86 inches)

  P(\bar X \geq 65.86 inches) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } } ) = P(Z \geq -2.57) = P(Z \leq 2.57)

                                                                        = <u>0.99492  or  99.5%</u>

<em>The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.</em>

<em />

Therefore, 99.5% of all samples of 21 of​ today's women in their 20's have mean heights of at least 65.86 ​inches.

3 0
3 years ago
How do you solve the equation 5x= 1 2/3
disa [49]
I hope it helps you get it right

3 0
3 years ago
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