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Brut [27]
2 years ago
15

W and y are supplementary. find m

Mathematics
1 answer:
Lunna [17]2 years ago
6 0
The answer to the question

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Which method would be the easiest way to solve the system
Makovka662 [10]
Elimination would be the best
6 0
3 years ago
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4x/3+3=x-2 <br>value of x ?​
Gekata [30.6K]

Answer:

x = - 15

Step-by-step explanation:

Given

\frac{4x}{3} + 3 = x - 2

Multiply through by 3 to clear the fraction

4x + 9 = 3x - 6 ( subtract 3x from both sides )

x + 9 = - 6 ( subtract 9 from both sides )

x = - 15

6 0
3 years ago
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HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!! CERTAIN ANSWERS AND I WILL MARK YOU AS BRAINIEST!!!! WISH YOU BEST OF LUCK HOPEFULLY ITS N
AURORKA [14]

Answer:

1)

Minimum is a 4th Degree

2)

Positive; Even

3)

x=-4, -1\text{ Odd Multiplicity}\\x=3\text{ Even Multiplicity}

Step-by-step explanation:

Part 1)

The minimum degree of our function will be 4.

Looking at the graph, we know that the graph crosses the x-axis at -4 and -1. Since it <em>crosses through</em> the x-axis at these two points, these two factors must have an odd multiplicity.

So, it can be anything 1, 3, 5, 7, etc.

However, we will choose the lowest one, 1.

Next, we know that the graph <em>bounces off</em> at 3.

So, it must have an even multiplicity. In other words, 2, 4, 6, 8, etc.

We choose the lowest one, 2.

Therefore, the minimum degree of our function will be 1+1+2 or 4.

Part 2)

The degree of our polynomial is (and will always be) even. Therefore, both ends of the graph will go in the same direction.

Recall the simplest even polynomial, the parent quadratic function. When the leading coefficient is positive, both of the ends go straight up.

This applies to all polynomials with even degrees.

Therefore, since the arms of the graph is going straight up towards positive infinity, the leading coefficient of our graph must be positive.

Part 3)

This is similar to Part 1.

We can see that the graph touches the x-axis at -4, -3, and 1. So, the zeros of the function is: x=-4, -1, 3

We know that it<em> passes through</em> x=-4 \text{ and } x=-1 . So, these two factors must have an odd multiplicity.

However, since the graph <em>bounces off</em> x=3, this factor must have an even multiplicity.

And we're done!

7 0
2 years ago
I need assistance!!!!
erastovalidia [21]

Answer:

Step-by-step explanation:

Because midpoints were used to make similar triangles we can say

AC=2(DE)

5x+12=2(9x-20)

5x+12=18x-40

-13x+12=-40

-13x=-52

x=4

AC=5x+12

AC=5(4)+12

AC=20+12

AC=32

3 0
2 years ago
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I don’t understand this helpp
Olenka [21]

Answer:

a. y2×

b.y1×

c.y1×

d.y2×

e.1×

4 0
2 years ago
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