Answer:
p²q³ + pq and pq(pq² + 1)
Step-by-step explanation:
Given
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Required
Collect like terms
We start by rewriting the expression
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Collect like terms
3p²q² -3p²q² - 3p²q³ +4p²q³ + pq
Group like terms
(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq
Perform arithmetic operations on like terms
(0) - (-p²q³) + pq
- (-p²q³) + pq
Open bracket
p²q³ + pq
The answer can be further simplified
Factorize p²q³ + pq
pq(pq² + 1)
Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)
Answer:
if angles shown are right angle then from corner to midpoint line if this is symettrical angles are 45 and 45. if area is asked of you need to
Step-by-step explanation:
To find the area of any right triangle, you simply multiply the lengths of the two sides that are perpendicular to each other, and then take half of that. if you could flip one of them and move it on top of the other, they would match exactly. The rectangle has an area of 2 × 4 = 8 square units.
Answer:
Step-by-step explanation:
hello :
note : the vertex form is :
ax²+bx+c = a(x+(b)/(2a))²- delta/4a² and delta = b²- 4ac
in this exercice you have : a =1 b = -1 and c= 3
continu ..........
Answer:
y=3×-11
Step-by-step explanation:
y=m+c
m=7-1÷6-4
m=6÷2
m=3
y=3+c
7=3(6)+c
7-18=c
-11=c
y=3×-11
