A random sample of 41 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $19.55 per car. The p

Question

andrew11 [14]

2 years ago

10

A random sample of 41 cars in the drive-thru of a popular fast food restaurant revealed an average bill of $19.55 per car. The p

opulation standard deviation is $6.33. Estimate the mean bill for all cars from the drive-thru with 97% confidence.

Mathematics

1 answer:

Rashid [163] · Answer 1 · 2022-10-07T11:56:44+03:00

Rashid [163]2 years ago

8 0

Answer:

$19.55\pm2.145$

Step-by-step explanation:

We use the equation $\bar x\pm z^*\sigma/\sqrt n$ , where $\bar x=19.55$ , $\sigma=6.33$ , $n=41$ , and $z^*=2.17$ . We obtain $z^*$ from the z-score of a 0.97 confidence level.