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Mademuasel [1]
3 years ago
7

Which is a prime number 21 23 25 27 29

Mathematics
1 answer:
UNO [17]3 years ago
8 0

Answer:

29 :)

it is 29 because 29 falls under all the prime number characteristics

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Derivative of sin11xcos11x
diamong [38]
Hello here is a solution :
f'(x) =( sin11x)'cos11x +<span>sin11x(cos11x)'
(sin(ax+b))'=a cos(ax+b)
</span>(cos(ax+b))'=-a sin(ax+b)
f'(x) = 11 cos11xcos11x-11sin11xsin11x
f'(x) = 11(cos11x)²-11(sin11x)²


6 0
3 years ago
the length of a boat is 10.8 m Boris buys a scale model of the boat the scale of the model is 1 to 18 work out the length of the
Wittaler [7]

Answer:

The size of the scale model is 60 centimeters.

Step-by-step explanation:

Given that the length of a boat is 10.8 m, and Boris buys a scale model of the boat whose ratio is 1 to 18, to determine the length of the scale model of the boat in centimeters the following calculation must be performed:

1m = 100cm

10.8 m = (10.8 x 100) = 1080 cm

1080/18 = X

60 = X

Therefore, the size of the scale model is 60 centimeters.

4 0
3 years ago
Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

6 0
2 years ago
A student said that since –9 is less than 4, then |–9| is less than |4|. Is the student correct? Explain why or why not
Leno4ka [110]
The student is not correct.

Absolute value means distance from zero
|-9| = 9
|4| = 4

Since 9 is greater than 4,
|-9| is greater than |4|

In other words, -9 is further from zero then 4
5 0
3 years ago
The volume of a cylinder is 225π cubic inches,
aleksklad [387]

The value of the height of the cylinder is 25cm.

According to the statement

we have to find that the height pf the cylinder with the given value of the volume.

So, For this purpose we know that the

The volume of a cylinder is the density of the cylinder which finds that the amount of material it can carry. Cylinder's volume is given by the formula, πr^2h.

From the given information:

The volume of a cylinder is 225π cubic inches, and the radius of the cylinder is 3 inches.

Then

volume = πr^2h

225π = π3^2h

Now, solve it then

225 = 9h

h = 25.

The value becomes 25.

So, The value of the height of the cylinder is 25cm.

Learn more about volume of a cylinder here

brainly.com/question/9554871

#SPJ9

5 0
1 year ago
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