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Mademuasel [1]
3 years ago
7

Which is a prime number 21 23 25 27 29

Mathematics
1 answer:
UNO [17]3 years ago
8 0

Answer:

29 :)

it is 29 because 29 falls under all the prime number characteristics

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What is the sum of the infinite geometric series with a1=42 and r=6/5?
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This infinite sum is given by

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S =  ------  but ONLY if r<1.  Here, r>1, so the infinite sum does not exist.    
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How many cm make 1m? Can some pls tell me from mm to km
Alborosie

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If f(x) = 4x and g(x) = x^3, then what is f(g(x))?
kompoz [17]

Answer:

f(g(x)) = 4x³

Hence, option C is true.

Step-by-step explanation:

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f(g(x)) = ?

solving the f(g(x))

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f(g(x)) = 4x³

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3 years ago
The Laplace Transform of a function f(t), which is defined for all t &gt; 0, is denoted by L{f(t)} and is defined by the imprope
lesya692 [45]

(1) D

L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt

Integrate by parts, taking

u = t \implies \mathrm du=\mathrm dt

\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}

Then

L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}

L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}

(2) A

L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt

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L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}

7 0
3 years ago
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