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pav-90 [236]
4 years ago
14

On a coordinate plane, a rectangle has points K prime (1, 3), L prime (2, 3), M prime (2, negative 3), N prime (1, negative 3).

A rectangle was rotated 270° about the origin. The image is shown. Which points are vertices of the pre-image? Check all that apply.
Mathematics
1 answer:
Sidana [21]4 years ago
7 0

Answer:

M(3,2) and N(3,1)

Step-by-step explanation

trust me

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In-s [12.5K]
Answer: B

Explanation: an isosceles triangle has 2 sides that are the same, so if the base angles are both 34° then you can multiply that by 2 to get 68°. After that you know that you're still missing one of the angles so that missing angle is x. The equation you can set up to solve for x is the following: 68° + x° = 180°

Hope this helped! :)
8 0
3 years ago
Solve the inequality 2-x<7​
dedylja [7]

Answer:

x > -5

Step-by-step explanation:

8 0
3 years ago
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There are 40 houses in a neighborhood • company X provides electricity to 1/5 of the houses • company Y provides electricity to
Katena32 [7]
Answer: 1/5 or 8 houses. Company X provides electricity to 8 houses, Company Y provides to 24 houses, so that would mean Company Z provides 8
8 0
3 years ago
Read 2 more answers
Find X and Y and show please show calculations
torisob [31]

Answer:

Y = 90

X = 52

Step-by-step explanation:

Y is on a straight line. The sum of the angles on a straight line is 180.

The only other angle (that is marked) on this straight line, is a 90 degree one. So, <y + 90 = 180.

<y = 90.

Now <x + 38 = 90

so, x = 52

6 0
3 years ago
Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method
antoniya [11.8K]

Answer:

a

The estimate is  - 0.0265\le  K \le  0.0465

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is  n_1 = 400

The number of faulty breaks of method A is  X_1 = 32

 The number of microchips broken in method B is  n_2  = 400

 The number of faulty breaks of method A is  X_2 = 32

  The proportion of the faulty breaks to the total breaks in method A is

       p_1 = \frac{32}{400}

      p_1 = 0.08

 The proportion of the faulty to the total breaks in method B is

      p_2 =  \frac{28}{400}

     p_2 =  0.07

For this estimation the standard error is  

      SE =  \sqrt{ \frac{p_1 (1 - p_1)}{n_1}  + \frac{p_2 (1- p_2 )}{n_2} } }

  substituting values

       SE =  \sqrt{ \frac{0.08 (1 - 0.08)}{400}  + \frac{0.07 (1- 0.07 )}{400} } }

      SE = 0.0186

The z-values of confidence coefficient of 0.95 from the z-table is  

       z_{0.95} =  1.96

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

        K = [p_1 - p_2 ] \pm z_{0.95} * SE

substituting values

        K = [0.08 - 0.07 ] \pm 1.96 *0.0186

         K  =  - 0.0265 \ or  \ K  =  0.0465

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is  

      - 0.0265\le  K \le  0.0465

3 0
3 years ago
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