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3 years ago

FIRST PERSON WHO ANSWERS THIS WILL BE BRAINLIEST

Mathematics

1 answer:

djverab [1.8K]3 years ago

3 0

Answer:

2.- 100

Step-by-step explanation 1:

$\frac{7}{25} + \frac{3}{4} = \frac{28}{100} + \frac{75}{100} = \frac{103}{100}$

↑ As we can see, the only common multiple between 4 and 25 that is given to is 100.

Step-by-step explanation 2:

$\frac{(7 * 4) + (3 * 25)}{4 * 25} = \frac{28 * 75}{100} = \frac{103}{100}$

↑ Another way of knowing the answer is by using a fraction solving method. As we can see, the denominator is once again 100.

Hope it helped,

BiologiaMagister

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Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

given data:

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α/2 = 0.05/2 = 0.025,

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$ME = Zc * σ \sqrt{n}$

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CI = (57.12 , 59.48)

Given data:

mean, $\bar X = 58.3$

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

$ME = zc * σ \sqrt{n}$

$ME = 1.96 * 3\sqrt{100}$

ME = 0.59

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})$

CI = (57.71 , 58.89)

sample mean, $\bar X = 58.3$

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

$ME = Zc * σ \sqrt{n}$

$ME = 2.58 * 3\sqrt{100}$

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$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

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Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

$n \geq (zc *σ/E)^2$

$n = (2.58 * 3/0.5)^2$

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