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tino4ka555 [31]
3 years ago
8

Which of the following shows the graph of a line with a slope of 6/5 and a y intercept of -3?

Mathematics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

The correct option is 1.

Step-by-step explanation:

It is given that the slope of the line is 6/5 and y intercept is -3. It means the line must be passes through the point (0,-3).

The slope intercept form of a line is

y=mx+b

where, m is slope and b is y-intercept.

Substitute m=6/5 and b=-3 in the above equation to find the equation of line.

y=\frac{6}{5}x+(-3)

So, the equation of line is y=\frac{6}{5}x+(-3).

Substitute y=0 in the above equation to find the x-intercept of the line.

0=\frac{6}{5}x-3

Add 3 on both the sides.

0+3=\frac{6}{5}x-3+3

3=\frac{6}{5}x

Multiply both sides by 5.

15=6x

Divide both sides by 6.

\frac{15}{6}=x

2.5=x

The x-intercept of the line is 2.5. It means the line must be passes through the point (2.5,0).

Since only in graph 1, the line passes through the points (0,-3) and (2.5,0), therefore the graph 1 represents the required line and option 1 is correct.

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What is the product? 6.4(-3.7) -23.68 23.68 11.84 -20.48
djyliett [7]
Multiplying decimals:

First, multiply like a normal number.
64 × 37 = 2368

Add up the number of decimal points from your original numbers to find out where you should put the decimal point on your result.
6.4 has one decimal place, and -3.7 has one decimal place.
Our result should have two decimal places. (1+1)

23.68

Because we multiplied by a negative number, our result should be negative, too.

-23.68
6 0
3 years ago
PLS HELP ME WITH THIS QUESTION!!! AND PLS PLS PLS DO EXPLAIN. I WILL MARK THE BEST ANSWER BRAINLIEST
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He number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the
denis-greek [22]

The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:

A(t)=136(1.123)^{4t}

Answer:

   Option A. 59%

Explanation:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::

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Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1

t=1\\\\ A(1)=136(1.123)^4\\\\\\t=2\\ \\ \\A(2)=136(1.123)^8\\ \\ \\A(2)/A(1)=1.123^8/1.1123^4=1.123^4=1.590

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Step-by-step explanation:

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