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lorasvet [3.4K]
3 years ago
13

How do I find a perimeter

Mathematics
2 answers:
adell [148]3 years ago
8 0

The perimeter is the total distance around the sides of a 2 dimensional shape. To calculate a perimeter, add up all the side lengths around the shape

Example:

2 by 5 rectangle

2 of the sides are 2 long

2 of the sides are 5 long

Add up the measures:

2 + 2 + 5 + 5 = 14

perimeter is 14

german3 years ago
5 0
By adding all of the numbers on the the outside lines
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I need help with this question. Can you please help me. I’ll give you 18 points if it’s correct
lukranit [14]

Answer:

34.4

Step-by-step explanation:

Using Triangle Sum Theory, you see that the triangles are similar. They have the same angle measurements. That means their corresponding sides are proportional.

\frac{MN}{NO} = \frac{PQ}{QR}

\frac{14}{11} = \frac{PQ}{27}

Cross multiply

14(27) = 11(PQ)

378 = 11(PQ)

\frac{378}{11} = PQ

PQ = 34.4

7 0
3 years ago
A car factory made 30 cars with a sunroof and 9 cars without a sunroof. What is the ratio of
AfilCa [17]

Answer:

30:9

Step-by-step explanation:

3 0
3 years ago
Which point is on the circle centered at the origin with a radius of 5 units?
Aleonysh [2.5K]

Answer:

(2,√21)

Step-by-step explanation:

The circle centered at the origin has equation:

{x}^{2}  +  {y}^{2}  = 25

Any point that satisfies this equation lie on this circle.

When x=2, we substitute and solve for y.

{2}^{2}  +  {y}^{2}  = 25 \\ 4 +  {y}^{2}  = 25 \\  {y}^{2}  = 25 - 4 \\ {y}^{2}  = 21

Take square root to get:

y =  \pm \sqrt{21}

Therefore (2,-√21) and (2,√21) are on this circle.

From the options, (2,√21) is the correct answer

3 0
3 years ago
Read 2 more answers
49x^2 -_x + 16<br><br> Can someone help with the missing number
mihalych1998 [28]

Step-by-step explanation:

I'm guessing this is competing the perfect square

so it's 56

5 0
3 years ago
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Best answer gets the brainliest!<br> Find $a/b$ when $2\log{(a -2b)} = \log{a} + \log{b}$.
andrey2020 [161]

By some properties of logarithms, rewrite the equation as

2\log(a-2b) = \log(a) + \log(b) \\\\ \log(a-2b)^2 = \log(ab)

so that

(<em>a</em> - 2<em>b</em>)² = <em>ab</em>

Expand the left side:

<em>a</em> ² - 4<em>ab</em> + 4<em>b</em> ² = <em>ab</em>

Rearrange terms to get a quadratic equation in <em>a</em>/<em>b</em> :

<em>a</em> ² - 5<em>ab</em> + 4<em>b</em> ² = 0

<em>b</em> must be greater than 0, otherwise log(<em>b</em>) doesn't exist, and the same goes for <em>a</em>. So we can divide by <em>b</em> ² to get

<em>a</em> ²/<em>b</em> ² - 5<em>a</em>/<em>b</em> + 4 = 0

Factorize and solve for <em>a</em>/<em>b</em> :

(<em>a</em>/<em>b</em> - 4) (<em>a</em>/<em>b</em> - 1) = 0

==>   <em>a</em>/<em>b</em> = 4   or   <em>a</em>/<em>b</em> = 1

However, if <em>a</em>/<em>b</em> = 1, then <em>a</em> = <em>b</em> makes <em>a</em> - 2<em>b</em> = -<em>b</em>. But we must have <em>b</em> > 0, so we omit the second solution and end up with

<em>a</em>/<em>b</em> = 4

5 0
3 years ago
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