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Lady bird [3.3K]
10 months ago
9

sarah spent a total of 10 on oranges and apples at the supet market. if she spent 3 dollars less for oranges than she did on app

les how much did sarah spend on oranges
Mathematics
1 answer:
beks73 [17]10 months ago
3 0

Let's write 2 equations from the two statements given.

<em>Sarah spent 10 dollars on both oranges and apples</em>

<em />

Let the price of oranges be "x" and price of apples be "y", thus we can write:

x+y=10

Oranges cost 3 less than apples, thus we can say:

y-3=x

We can substitute this into the first equation and solve for y:

\begin{gathered} x+y=10 \\ y-3+y=10 \\ 2y=10+3 \\ 2y=13 \\ y=\frac{13}{2} \\ y=6.5 \end{gathered}

Thus, let's solve for x now,

\begin{gathered} x=y-3 \\ x=6.5-3 \\ x=3.5 \end{gathered}

We want the price of oranges (x), thus,

<em>Price of Oranges = $3.50</em>

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Answer:

70

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Katen [24]

(0.5, 1.3) is the correct answer

Step-by-step explanation:

Given equations are:

y = 4x-0.8\ \ \ Eqn1\\2x+y-2.3=0\ \ \ Eqn2

As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.

We can plot the graph of both equations using any online or desktop graphing tool.

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(0.5, 1.3) is the correct answer

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Step-by-step explanation:

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The authors of a paper describe an experiment to evaluate the effect of using a cell phone on reaction time. Subjects were asked
Serggg [28]

Answer:

a) The 99% confidence interval would be given by (24.409;24.979)  

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

525+2.01\frac{75}{\sqrt{47}}=546.99  

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

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