By applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
<em>See the image in the attachment for the referred diagram.</em>
<em />
- The two triangles, triangle AEC and triangle BDC are similar triangles.
- Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.
<em>This implies that</em>:
<em><u>Given:</u></em>

<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>
EC/DC = AE/DB



<u>b. </u><u>Find the length of </u><u>AB:</u>

AC = 6.15 cm
To find BC, use AC/BC = EC/DC.




Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:
a. 
b. 
Learn more here:
brainly.com/question/14327552
Answer:
(-4,9)
Step-by-step explanation:
substitute the given value for y into the first equation
x-5(-2x+1)=-49
distribute
x+10x-5=-49
add like terms
11x-5=-49
add 5 to both sides
11x=-44
divide both sides by 11
x=-4
now plug x into into the second equation
y=-2(-4)+1
y=8+1
add like terms
y=9
1 bed room = 12
2 bed room = 15
68 x 15 = 1020
57 x 12 = 684
-----------
1020 + 684 = $1704 (total made)
15 two-bed room + 12 one-bed room = 27 rooms in all
It would be 190 km because you do 5 x 3 to get 15 add a 0 at the end of it. Than at 40 because .8 of 150 is 40. Then 150+40= 190
9514 1404 393
Answer:
DE = 86
EF = 84
Step-by-step explanation:
We assume that point E lies on segment DF, so that ...
DE + EF = DF
(3x +20) +(2x +40) = 170
5x = 110 . . . . . . . . . . . . . . . collect terms, subtract 60
x = 22 . . . . . . . . . . . . divide by 5
DE = 3×22 +20 = 66 +20 = 86
EF = 2×22 +40 = 44 +40 = 84