<span>If points R and S are contained in a plane, then RS is entirely contained in that plane.</span>
Answer:
Step-by-step explanation:
<u>∴ ΔABC ≈ ΔADE</u>
∴
↑1 ↑ 2 ↑3
→
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Radius of cone is2.39cmor 2.4cm
volume of cone=45.19cm^3
Pi×r^2×h/3=45.19
22×r^2×7.5/7=45.19×3
r^2=45.19×3×7/22×7.5
r^2=948.99/165
r^2=5.7514545
r=2.39
Or we can say r=2.4cm
The numerator is the number above
1- The coordinate of J(-3,-6)
Since it's a dilatation, the original J coordinates are 2/3 of the dilated one or
the dilated point will be 3/2 greater than the original:
J' [-3(3/2), -6(3/2)] = J' (-9/2 , -9)
2-JKM is a right triangle because the hypotenuse KM = 15.3.
PROOF: Applying Pythagoras:
KM² = 8²+13² , KM² =233; KM =√233 = 15.3
3- As per the figure MB=MA=88 cm . So we can calculate MB = 2X88 = 176 Moreover triangles BAC and BMN are similar, then we can write:
BM/BA = MN/AC or 88/176 = MN/116 AND MN = 58 cm
Second method (quicker): M is the middle of BA, and N, the middle of BC:
In a triangle, the line joining the mid points of 2 sides is parallel to the 3rd side and equal half of this side: Hence 116/2 = 58