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3 years ago

Elise wants to divide a sum of money between Hannah and Adil in the ratio

Mathematics

1 answer:

ioda3 years ago

6 0

Answer:

Hanna said is correct because the money is divided in the ratio 2:3

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Determine whether the statement is always, sometimes, or never true: Two points A and B determine a line. *

alisha [4.7K]

Answer:

sometimes

Step-by-step explanation:

8 0

3 years ago

Which is the completely factored form of 12x3 – 60x2 + 4x – 20?

Natalija [7]

Answer:

$4(x-5)(3{x}^{2}+1)$

Step-by-step explanation:

1) Find the Greatest Common Factor (GCF).

1 - What is the largest number that divides evenly into $12x^3,-60x^2,4x,$ and $-20$ ?

It is $4.$

2 - What is the highest degree of $x$ that divides evenly into $12x^3,-60x^2,4x,$ and $-20$ ?

It is 1, since $x$ is not in every term.

3 - Multiplying the results above,

The GCF is 4.

2) Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

$4(\frac{12{x}^{3}}{4}+\frac{-60{x}^{2}}{4}+\frac{4x}{4}-\frac{20}{4})$

3) Simplify each term in parentheses.

$4(3{x}^{3}-15{x}^{2}+x-5)$

4) Factor out common terms in the first two terms, then in the last two terms.

$4(3{x}^{2}(x-5)+(x-5))$

5) Factor out the common term $x-5$ .

$4(x-5)(3{x}^{2}+1)$

5 0

2 years ago

90=20+70 use the distributive property and the GCF OF 20 and 70 to write another related expression for 90 could you write anoth

juin [17]

90 = 20 + 70.....GCF of 20 and 70 is 10
90 = 10(2 + 7) <==

can u write another expression using a different common factor...yes
90 = 20 + 70.....common factor is 5
90 = 5(4 + 14) <==

8 0

3 years ago

If there are twice as many bicycles as scooters and there are 945 vehicles in total. How many bicycles and scooters are there in

alexandr402 [8]

Answer:

Bicycles = 315

Scooters = 630, basic mathematics. The most effective method for these questions is substitution. But I might have intermingled them so double check

3 0

3 years ago

I need to solve xy I am so confused please

pychu [463]

Answer:

Step-by-step explanation:

In the question it’s given that : y=|x| => even if x will be a negative number,y will be positive.

1) -3 ; 3 ; (-3,3)

2) -2 ; 2 ; (-2,2)

3) -1 ; 1 ; (-1,1)

4) 0 ; 0 ; (0,0)

5) 1 ; 1 ; (1,1)

6) 2 ; 2 ; (2,2)

7) 3 ; 3 ; (3,3)

8 0

3 years ago