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Natasha2012 [34]
3 years ago
15

of 100 children 3 quarters have pets 40 kids have a dog and 18 have a cat how many kids have other kinds of pets

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

17 kids have other kinds of pets

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What is the opposite of 4
horsena [70]
Negative 4 or -4 is the answer
8 0
3 years ago
Bob and mark talk about their families. Bob says he has 3 kids, the product of their ages is 72. He gives another clue: the sum
pychu [463]
I can only give possible combination of the ages. Had the sum of the ages been given, then the 3 specific numbers would have been derived.

We need to do prime factorization of 72.

72 ÷ 2 = 36
36 ÷ 2= 18
18 ÷ 2 =  9
  9 ÷ 3 =  3
  3 ÷ 1 = 1

1 x 2 x 2 x 2 x 3 x 3 = 72

Possible combinations:

1 x 8 x 9 = 72           1 + 8 + 9 = 18
1 x 4 x 18 = 72         1 + 4 + 18 = 23
2 x 4 x 9 = 72            2 + 4 + 9 = 15
3 x 4 x 6 = 72            3 + 4 + 6 = 13


3 0
3 years ago
The pair of square pyramids are similar. Use the given information to find the scale factor of the smaller square pyramid to the
Mrrafil [7]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array}\\\\
-----------------------------

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\stackrel{\stackrel{pyramids}{scale~factor}}{\cfrac{small}{large}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{64}}{\sqrt[3]{343}}\implies \cfrac{s}{s}=\cfrac{4}{7}\implies 4:7
8 0
3 years ago
Robin spent $ 28 at an amusement park For admission and rides. If she paid $6 for admission and rides cost $2 each what is the t
motikmotik

Answer:

11 rides

Step-by-step explanation:

let the total amount be y

and let the number of ride be x

the expression for the situation is y=mx+c

given

total amount=$28

admission fee= $6

cost per ride=$2

we are expected to find x

substitute into the expression we have

28=2x+6

28-6=2x

22=2x

divide boths sides by 2 we have

x=22/2

x=11

the number of rides is 11

4 0
3 years ago
Given a+b=7 and a–b=3, find:<br><br> 2^a*2^b
seropon [69]

Answer:

128

Step-by-step explanation:

5+2=7

5-2=3

2^5=32

2^2=4

32*4=128

Hope this helps:)

7 0
3 years ago
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