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olchik [2.2K]
2 years ago
9

Given SQ = 5x + 19 and PQ = 83 – 3.x, find x. Round your answer to the nearest tenth.

Mathematics
1 answer:
emmainna [20.7K]2 years ago
5 0

Answer:

no common tangent. Determine whether is tangent to . Justify your ... The lengths given are in feet. ... triangle will have lengths of JK = 12 + 7 or 19, KL = ... no common tangent. eSolutions Manual - Powered by Cognero. Page 3. 10-5 ... Round to the nearest tenth. Yes; 80 = 80. Find x. Assume that segments that ...

Step-by-step explanation:

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Which of the following represents an equation of a line parallel to one whose equation is 2x + 8x = 18
Naya [18.7K]

Answer:

y=-4x+3

Step-by-step explanation:

it does not show the equations that are following

but the main thing you need to know is that when two lines are parallel they have the same slope

and do you mean 2x+8y=18 not x?

edit:

answer choices: y=-4x+3, y=8x-2, y=4x+7, y=-8x+9

2y+8x=18

first change that equation to slope intercept form to find the slope

2y = -8x+18 -> y = -4x+9

slope is -4

so the answer is y=-4x+3 because it also has a slope of -4

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3 years ago
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I think It is be but idk as I am in year 7
8 0
3 years ago
Read 2 more answers
-4x+3y= -2 y=x -1<br><br> Solve for X and Y
Rzqust [24]
(xy)=(9,4). Hope this helps
6 0
3 years ago
The table below lists the masses and volumes of several pieces of the same type of metal. There is a proportional relationship b
galben [10]
In effect, there is a proportional relationship between the mass and the volume of the pieces of metal. The equation of the line that adapts to the given data is given by: y = 0.1174x. Therefore the proportionality constant is 0.1174
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The graph of the line passes through the points (0,-2) and (6,0). What is the equation of the line?
valina [46]

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{0}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{0-(-2)}{6-0}\implies \cfrac{0+2}{6}\implies \cfrac{2}{6}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=\cfrac{1}{3}(x-0) \\\\\\ y+2=\cfrac{1}{3}x\implies y=\cfrac{1}{3}x-2

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3 years ago
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