Hello!

Explanation:
↓↓↓↓↓↓↓↓↓↓
First you had to add by
from both sides of the equation.

Simplify it should be the correct answer.

Answer⇒⇒⇒⇒⇒r=2
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-Charlie
Answer:
here is an example to guide you
Step-by-step explanation:
To find how much paper for the model, you will use the formula for area of a square and area of a triangle.
A = bh
7.2 x 7.2
A = 51.84 cm²
A = 1/2bh
1/2 x 7.2 x 6
A = 21.6 cm²
21.6 cm² x 4 = 86.4 cm²
86.4 + 51.86=138.3
You will need 138.3 cm² of paper.
Given that the ball was rolling with an initial velocity of 4.80 m/s, when it encountered the ramp.
Given that the accerelation with which it rolled over the ramp was

and that the ranp is 0.750 m long.
The final velocity of an object with an initial velocity, u, with an accerelation, a, moving through a distance, s is given by

Thus, the <span>final velocity of the ball when it reaches the top of the ramp is given by

</span>
Answer:
c
Step-by-step explanation:
9x=81
9x/9=81/9
x=9
Answer:
m ∠RMK = 51°
Step-by-step explanation:
m ∠JMK = m ∠RMK + m ∠JMR
10x + 19 = 7x - 26 + 6x + 12
10x +19 = 13x -14
19 = 3x -14
33 = 3x
11 = x
m ∠RMK = 7(11) - 26 = 51°
m ∠JMR = 6 (11) + 12 = 78