Answer:
24 units
Step-by-step explanation:
Given is a circle with two chord BE and CD
BE and CD intersect at A
By circle chords intersection theorem we have
DA*AC = EA*AB
i.e. 8(15) = 5(AB)
Divide by 5 both the sides
AB =8(15)/5 = 8(3) = 24 units
Verify:
Let us check now whether chord intersection theorem is satisfied.
DA*AC = 8(15) = 120
EA*AB = 5(24) = 120
Since these two equal, we verify that answer is right.
If you would like to know which of the following steps should be performed to eliminate variable d first, you can find this using the following steps:
equation a: 2c = d - 8 /*(-3)
equation b: c = 3d + 8
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-6c = -3d + 24
c = 3d + 8
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-6c + c = -3d + 24 + 3d + 8
-5c = 32
5c = -32
c = -32/5
<span>The correct result would </span>be: <span>multiply equation a by −3.</span>
Filling in the boxes:
Top row outside box: 3c and 8
Second row outside box: - or -1
Inside box: -3c and -8
Expanded: -3c - 8
Answer:
congruent angles have same number of shape and size