Differentiate both sides, treating 
as a function of 
. Let's take it one term at a time.
Power, product and chain rules:
Product and chain rules:
Product and chain rules:
The derivative of 0 is, of course, 0. So we have, upon differentiating everything,
Isolate the derivative, and solve for it:
(See comment below; all the 6s should be 2s)
We can simplify this a bit by multiplying the numerator and denominator by to get rid of that fraction in the denominator.
Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,
Hence, this is the required solution.
0.300+0.030+0.004 hope this helps
We are given with two equations 2x − 3y = −1 and <span>11x − 9y = −13. The problem says that when the first equation is multiplied by -3 which results to -6x + 9y = 3, the sum of the resulting equation and the second one is equal to 5x = -10. We verify this: -6x + 11x = 5x while -9 y and 9 y cancels out. 3+-13 equals -10. Hence the total is really 5x = - 10.</span>
