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4 years ago

11

A point is one-dimensionalO A. TrueO B. FalseSUBMIT

2 answers:

Artyom0805 [142]4 years ago

7 0

A. I took a educated guess

Vanyuwa [196]4 years ago

4 0

Answer:

false!!

Step-by-step explanation:

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What is the effect on the graph of the parent function f(x) = x when f(x) is replaced with f(x) + 3?

VladimirAG [237]

Don't make the mistake of saying that the new function is up above the given function. f(x) + 3 is not above f(x) = x. f(x) + 3 is below f(x).

The answer is B <<<<<=====

y + 3 = x is the way you can think of it.
y = x - 3 is what it is. If you have a graphing calculator, graph it. You want to see that it is below f(x) = x or going down.

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4 years ago

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Solve for x: −2x + 5 < 7

Neko [114]

Inequality Form = X > -1

Interval Notation = (-1,∞)

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3 years ago

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inna [77]

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The right answer is <u>D) 8.8</u>

Step-by-step explanation:

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4 years ago

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A gift box has the shape of a rectangular prism. How much wrapping paper do you need to cover the box?

Natasha_Volkova [10]

Answer:

768 in²

Step-by-step explanation:

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Surface Area = 2(210 + 90 + 84)

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Surface Area = 768

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3 years ago

There are 8 rows and 8 columns, or 64 squares

lawyer [7]

Complete Question:

There are 8 rows and 8 columns, or 64 squares on a chessboard.

Suppose you place 1 penny on Row 1 Column A,

2 pennies on Row 1 Column B,

4 pennies on Row 1 Column C, and so on …

Determine the number of pennies in Row 1

Determine the number of pennies on the entire chessboard?

Answer:

255 in the first row

18,446,744,073,709,551,615 in the entire board

Step-by-step explanation:

Given

$Rows = 8$

$Columns = 8$

Solving (a): Number of pennies in first row

The question is an illustration of geometric sequence which follows

$1,2,4....$

Where

$a =1$ --- The first term

Calculate the common ratio, r

$r = \frac{T_2}{T_1} = \frac{4}{2} = 2$

The number of pennies in the first row will be calculated using sum of n terms of a GP.

$S_n = \frac{a(r^n - 1)}{n - 1}$

Since, the first row has 8 columns, then

$n = 8$

Substitute 8 for n, 2 for r and 1 for a in $S_n = \frac{a(r^n - 1)}{r - 1}$

$S_8 = \frac{1 * (2^8 - 1)}{2 - 1}$

$S_8 = \frac{1 * (256 - 1)}{1}$

$S_8 = \frac{1 * 255}{1}$

$S_8 = 255$

Solving (b): The entire board has 64 cells.

So:

$n = 64$

Substitute 64 for n, 2 for r and 1 for a in $S_n = \frac{a(r^n - 1)}{r - 1}$

$S_{64} = \frac{1 * (2^{64} - 1)}{2 -1}$

$S_{64} = \frac{(2^{64} - 1)}{1}$

$S_{64} = \frac{(18,446,744,073,709,551,616 - 1)}{1}$

$S_{64} = \frac{18,446,744,073,709,551,615}{1}$

$S_{64} = 18,446,744,073,709,551,615$

5 0

3 years ago