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oksian1 [2.3K]
4 years ago
10

11. 2(9x + 15)- 2(8 + 2x) 12.(7x - 12) - 2(3x + 10) Help pls

Mathematics
1 answer:
algol [13]4 years ago
6 0
Do PEMDAS SEE which one comes first
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Solve for X<br><br> 4X-(9-3X)=8X-1
Nataliya [291]
4x - (9 - 3x) = 8x - 1

4x - (9) - -(3x) = 8x - 1

4x - 9 + 3x = 8x - 1

7x - 9  = 8x - 1        (-8x from each side)

-x - 9 = -1                (+9 to each)

-x = 8                     (divide -1 from each side)

x = -8
7 0
3 years ago
We are working with system of equations
Yakvenalex [24]
8m + 2q = 18.00
3m + q =. 7.50


8m + 2q = 18.00
-6m - 2q = -15.00

2m = 3.00

m = $1.50 each muffin

3(1.50) + q = 7.50

4.50 + q = 7.50

q= $3.00 for each quarter of milk
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4 years ago
Given line AB with point P above, Grace was asked to construct a line parallel to line AB. She used her compass and straight edg
Doss [256]
The answer is <span>D i took the test</span>
8 0
3 years ago
Read 2 more answers
PQ has endpoints at P(7,-11) and Q(-5,-8). Find the slope of segment PQ.
GalinKa [24]
Work shown above! Answer is C

6 0
3 years ago
You have three online accounts and three different banks valued at: bank “A” $250.67, 12% interest, bank “B” $765.13, 7% interes
larisa [96]

The average interest gained from three accounts in one year is $913.224

<u>Explanation:</u>

Given:

Bank A:

Principal, P₁ = $250.67

Rate, r₁ = 12 %

Bank B:

Principal, P₂ = $765.13

Rate, r₂ = 7 %

Bank C:

Principal, P₃ = $28500.36

Rate, r₃ = 9 %

Interest from Bank A:

Interest = \frac{p X r X t}{100}\\\\I = \frac{250.67 X 12 X 1}{100} \\\\I = 30.0804

Interest from Bank B:

Interest = \frac{p X r X t}{100}\\\\I = \frac{765.13 X 7 X 1}{100} \\\\I = 53.5591

Interest from Bank C:

Interest = \frac{p X r X t}{100}\\\\I = \frac{28500.36 X 9 X 1}{100} \\\\I = 2565.0324

Average interest gained from three accounts in one year :

I = \frac{30.0804+53.5591+2656.0324}{3} \\\\I = 913.224

Therefore, average interest gained from three accounts in one year is $913.224

7 0
3 years ago
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