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3 years ago

What about this one y'all please help me

Mathematics

1 answer:

Eva8 [605]3 years ago

5 0

Angles 5 and 6 are not congruent because they are on the same line, so the answer is I

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Solve for X: 3(x+1)=-2(x-1)-4

jarptica [38.1K]

Answer

X= -1

Step-by-step explanation:

7 0

2 years ago

Find the area of the parallelogram with vertices Ps1, 0, 2d, Qs3, 3, 3d, Rs7, 5, 8d, and Ss5, 2, 7d.

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

8 0

2 years ago

In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the

ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

$P(A) = 0.01 , P(B) = 0.02$

We also know the probability that the memory and the hard drive fail simultaneously given by:

$P(A \cap B) = 0.0014$

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0

2 years ago

Help me plz ASAP<br> A.2<br> B.1/2<br> C.2/3<br> D.3/2

BARSIC [14]

Step-by-step explanation:

First and foremost, we can rule out B and C because they are less than one and would make the hexagon smaller instead of bigger. Now, when we measure the units, we see that it goes up by 2 squares on the graph. So, by process of elimination and measurement, we get the answer of A.

3 0

2 years ago

What is the maximum value that a marginal relative frequency can be? Explain.

mart [117]

The maximum value it can be would be 100%. The only times that it could be this high is when there is only a class on the frequency distribution table. Another way, is that there is only one column variable on the table (& or if there is only one row.) Any other time is will be less, but the maximum stays 100%.

3 0

3 years ago