Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
Answer:
Step-by-step explanation:
2(4 + x) = 34
4 + x = 34/2 = 17
x = 17 - 4 = 13
Answer: x=4
Step-by-step explanation:
1.5(x+4)-3=(x-2)
1.5x+6)-3=4.5x-9
1.5x+3=4.5x-9
+9 +9
1.5x+12=4.5x
divide 1.5x and 4.5
12=3x
/3 /3
x=4
Answer:
The answer is "3"
Step-by-step explanation:
In the question, some of the data is missing which is defined in the attached file. please find it.

That's why 3 is correct.
The answer is A because there are only acute angles