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IgorLugansk [536]
3 years ago
14

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

e is modeled using the equation h(t) = –16t2 + 48t + 190. What is the maximum height of the projectile? 82 feet 190 feet 226 feet 250 feet
Mathematics
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

The answer is 226

Step-by-step explanation:

BartSMP [9]3 years ago
3 0

Answer:

226 feet

Step-by-step explanation:

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What is the inverse of y=pi/2+sin x​
Alekssandra [29.7K]

Answer:

f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})

Step-by-step explanation:

The given function is

y=\frac{\pi}{2}+\sin x

To find the inverse of this function, we interchange x and y.

x=\frac{\pi}{2}+\sin y

we now solve for y.

x-\frac{\pi}{2}=\sin y

Take the sine inverse of both sides to obtain;

\sin ^{-1}(x-\frac{\pi}{2})=y

Hence the inverse of the given function is;

f^{-1}(x)=\sin ^{-1}(x-\frac{\pi}{2})

where \frac{\pi}{2}-1\le x\le \frac{\pi}{2}+1

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A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

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Answer:

Mixed Number Form:

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51.1 % is the answer.

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