A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil
e is modeled using the equation h(t) = –16t2 + 48t + 190. What is the maximum height of the projectile? 82 feet 190 feet 226 feet 250 feet
2 answers:
Answer:
The answer is 226
Step-by-step explanation:
Answer:
226 feet
Step-by-step explanation:
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Step-by-step explanation:
