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IgorLugansk [536]
3 years ago
14

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

e is modeled using the equation h(t) = –16t2 + 48t + 190. What is the maximum height of the projectile? 82 feet 190 feet 226 feet 250 feet
Mathematics
2 answers:
coldgirl [10]3 years ago
8 0

Answer:

The answer is 226

Step-by-step explanation:

BartSMP [9]3 years ago
3 0

Answer:

226 feet

Step-by-step explanation:

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