A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

Question

3 years ago

14

e is modeled using the equation h(t) = –16t2 + 48t + 190. What is the maximum height of the projectile? 82 feet 190 feet 226 feet 250 feet

2 answers:

coldgirl [10] · Answer 1 · 2022-04-13T08:26:18+03:00

8 0

Answer:

The answer is 226

Step-by-step explanation:

BartSMP [9] · Answer 2 · 2022-04-13T06:09:09+03:00

BartSMP [9]3 years ago

3 0

Answer:

226 feet

Step-by-step explanation: