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Kobotan [32]
3 years ago
6

Perform the multiplication, (7x2+a2)(x2–3a2)

Mathematics
1 answer:
aksik [14]3 years ago
8 0

Answer:

The given multiplied expression is

(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4

Step-by-step explanation:

Given expression is (7x^2+a^2)(x^2-3a^2)

To find the multiplication of the given expression :

(7x^2+a^2)(x^2-3a^2)

By using the distributive property to solve the given expression as below

(7x^2+a^2)(x^2-3a^2)=(7x^2)(x^2)+(7x^2)(-3a^2)+(a^2)(x^2)+(a^2)(-3a^2)

=7x^2.x^2-21x^2a^2+a^2x^2-3a^2.a^2

=7x^{2+2}-21x^2a^2+a^2x^2-3a^{2+2}  ( by using the property a^m.a^n=a^{m+n} )

=7x^4-21x^2a^2+a^2x^2-3a^4

Adding the like terms in the above expression we get

=7x^4-20x^2a^2-3a^4

Therefore (7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4

Therefore the given multiplied expression is

(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4

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:3

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N

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and  

N

2

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1

9

⋅

1

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9

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9

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(

1

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10

3

x

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10

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3

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3

x

2

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9

x

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1

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1

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x

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3

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x

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is the factorised form for the expression.

is the factorised form for the expression.

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