Question

Perform the multiplication, (7x2+a2)(x2–3a2)

Answer 1

Answer:

The given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Step-by-step explanation:

Given expression is $(7x^2+a^2)(x^2-3a^2)$

To find the multiplication of the given expression :

$(7x^2+a^2)(x^2-3a^2)$

By using the distributive property to solve the given expression as below

$(7x^2+a^2)(x^2-3a^2)=(7x^2)(x^2)+(7x^2)(-3a^2)+(a^2)(x^2)+(a^2)(-3a^2)$

$=7x^2.x^2-21x^2a^2+a^2x^2-3a^2.a^2$

$=7x^{2+2}-21x^2a^2+a^2x^2-3a^{2+2}$  ( by using the property $a^m.a^n=a^{m+n}$ )

$=7x^4-21x^2a^2+a^2x^2-3a^4$

Adding the like terms in the above expression we get

$=7x^4-20x^2a^2-3a^4$

Therefore $(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$

Therefore the given multiplied expression is

$(7x^2+a^2)(x^2-3a^2)=7x^4-20x^2a^2-3a^4$