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svet-max [94.6K]
3 years ago
14

Zoe cuts a raffia 4/5 meters long into 8 pieces of equal length. What is the length of each piece of raffia? Give answer in mete

rs.
Please tell me the final answer and how you got it.
Mathematics
1 answer:
sashaice [31]3 years ago
8 0
To find the answer, I first changed 4/5 into a decimal.
4/5 = 0.8

Next divided 0.8 with 8 because you are cutting the 4/5 meter raffis into 8 equal pieces.
0.8/8 = 0.1 meters

And if you need it in fraction form, its: 1/10 meters

Finished!
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Mrs.Anderson is giving a test in her third period class she has decided to record the amount of time that each student takes to
ICE Princess25 [194]

The graph Plot of the given results shown represents; A relation only

<h3>How to interpret a scatter plot?</h3>

For it to be a function, then no x-value can produce more than 2 y-values. However, we see that at x = 25, y has 2 values. Similarly, at x = 15, y has two values.

Thus, the graph plot can only be a relation as it is not a function as seen from the points plotted in the graph.

The complete question is;

Mrs. Anderton is giving a test in her third-period class. She has decided to record the amount of time that each student takes to finish the test (in minutes) and compare that to the grade each student receives on the test (out of 100). A plot of her results is below. Which of the following does this situation represent?

A. both a relation and a function

B. a function only

C. neither a relation nor a function

D. a relation only

Read more about Scatter Plot at; brainly.com/question/6592115

#SPJ1

8 0
2 years ago
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
(5+22) x (35-27) + 6^2
aksik [14]
What does ^ stand for?
7 0
3 years ago
What's the answer I'm confused yeahhhhhhhhhh
Fantom [35]
-3 2/5 - 5/6 = -127/30

-2/3 + 6 1/8 = 107/24

3 0
3 years ago
NEED HELP ASAP PLEASE ILL GIVE BRAINLIEST!!!
spayn [35]

Answer:

the answer is in the picture

Step-by-step explanation:

8 0
2 years ago
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