You could do the question the way it is written, but it is far easier to bring the negative power up to the numerator.
y= x^2 - 3. The derivative of that is
dy/dx = 2x The three is a constant and is always dropped when a derivative is taken
d(-3)/dx = 0
If you are a purist and want to solve the question the way it is written, you could do it this way.
dy/dx = d(1)/dx x^-2 - d(x^-2)/dx * 1
======================
(x^-2)^2
dy/dx = - (-2 x^ - 3) / x^-4
dy/dx = 2 x^-3 * x^4
dy/dx = 2 x^(-3 + 4)
dy/dx = 2x ^ 1
dy/dx = 2x <<<<< answer
Answer:
D
Step-by-step explanation:
Answer:
The real solutions are
![x=\sqrt[6]{6}\approx 1.35\\\\\:x=-\sqrt[6]{6}\approx -1.35](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B6%5D%7B6%7D%5Capprox%201.35%5C%5C%5C%5C%5C%3Ax%3D-%5Csqrt%5B6%5D%7B6%7D%5Capprox%20-1.35)
Step-by-step explanation:
The solution, or root, of an equation is any value or set of values that can be substituted into the equation to make it a true statement.
To find the real solutions of the equation 
:
![\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x^6}{5}=\frac{30}{5}\\\\\mathrm{Simplify}\\\\x^6=6\\\\\mathrm{For\:}x^n=f\left(a\right)\mathrm{,\:n\:is\:even,\:the\:solutions\:are\:}x=\sqrt[n]{f\left(a\right)},\:-\sqrt[n]{f\left(a\right)}\\\\x=\sqrt[6]{6}\approx 1.35\\\\\:x=-\sqrt[6]{6}\approx -1.35](https://tex.z-dn.net/?f=%5Cmathrm%7BDivide%5C%3Aboth%5C%3Asides%5C%3Aby%5C%3A%7D5%5C%5C%5C%5C%5Cfrac%7B5x%5E6%7D%7B5%7D%3D%5Cfrac%7B30%7D%7B5%7D%5C%5C%5C%5C%5Cmathrm%7BSimplify%7D%5C%5C%5C%5Cx%5E6%3D6%5C%5C%5C%5C%5Cmathrm%7BFor%5C%3A%7Dx%5En%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%2C%5C%3An%5C%3Ais%5C%3Aeven%2C%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dx%3D%5Csqrt%5Bn%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A-%5Csqrt%5Bn%5D%7Bf%5Cleft%28a%5Cright%29%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B6%5D%7B6%7D%5Capprox%201.35%5C%5C%5C%5C%5C%3Ax%3D-%5Csqrt%5B6%5D%7B6%7D%5Capprox%20-1.35)
Answer:
They are both right triangles
Step-by-step explanation:
The triangles are both the same shape but one is bigger than the other.
