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Katyanochek1 [597]
3 years ago
6

Show that the sum of the reciprocals of three different positive integers is greater than 6 times the reciprocal of their produc

t.
Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
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What is 5x+3 subtracted from 3x-6
Vikki [24]
The answer is 2x-3 :))((
3 0
4 years ago
Read 2 more answers
Question and answer choices are in the SS attached!!!! Pls help me! ty!
victus00 [196]

Answer:

B

Step-by-step explanation:

It's a right triangle, so the pythagorean theorem will be used a lot.

First, find the side length on the left.

25^2 = 7^2 + y

y = 24

Now, knowing that 7 - 3 = 4 (the smaller side length), I can use this theorem again to find x.

4^2 + 24^2 = x^2

x = \sqrt{592}

Just need to simplify it a little farther...

592 / 16 = 37, so B must be the answer.

3 0
3 years ago
Help please!What is the x-intercept of the line?X=33 Y=-22X=52 Y=-33X=71 Y=-44
tekilochka [14]

x intercept is -5

Explanation

Step 1

find the slope of the line:

when you know 2 points of the line, you can find the slope, by using:

\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}

then,Let

P1(33,-22)

P2(52,-33)

replace,

\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-33-(-22)}{52-33}=\frac{-33+22}{19}=\frac{-11}{19} \\ \text{slope}=-\frac{11}{19} \end{gathered}

Step 2

find the equation of the line

y-y_1=slope(x-x_1)\rightarrow equation

let

\begin{gathered} \text{slope}=-\frac{11}{19} \\ P1(33,-22) \end{gathered}

replace,

\begin{gathered} y-y_1=slope(x-x_1)\rightarrow equation \\ y-(-22)=-\frac{11}{19}(x-33) \\ y+22=-\frac{11}{19}x+\frac{363}{19} \\ to\text{ isolate y, subtract 22 in both sides} \\ y+22-22=-\frac{11}{19}x+\frac{363}{19}-22 \\ y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \end{gathered}

now, we have the equation of the line, to get the x intercetp ( it is when y=0)

replace

\begin{gathered} y=-\frac{11}{19}x-\frac{55}{19}\rightarrow equation\text{ of the line} \\ 0=-\frac{11}{19}x-\frac{55}{19} \\ \text{isolate x} \\ \frac{11}{19}x=-\frac{55}{19} \\ 11x=-\frac{55\cdot19}{19} \\ 11x=-55 \\ \text{divide both sides by 11} \\ \frac{11x}{11}=\frac{-55}{11} \\ x=-5 \end{gathered}

so, the x intercetp is -5.

I hope this helps you

6 0
1 year ago
For every 10 fish you have, you need 5 gall how many gallons pf water do u have for 1 fish
frutty [35]
10/5 = 1/x
cross multiply
10x = 5
x = 5/10
x = 1/2...u need 1/2 gallon per fish
4 0
3 years ago
Which set of expressions is not equivalent?
Anna11 [10]

Answer:

no

Step-by-step explanation:

7 0
3 years ago
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